You look in the sky and see two jetliners that you know are of equal size, yet one appears to be much larger. Because of your kn
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As per the question the object is placed at a distance of 8 mm from a concave spherical mirror.
Hence the object distance [u] = 8 mm.
As object distance is measured opposite to the direction of light,the sign for u will be negative.
Hence u = -8 mm
The image is formed at a distance of 16 mm in front of the mirror.
Hence the image distance [v ]= 16 mm.
As V is measured opposite to the direction of light,its sign convention will be negative.
Hence v = -16 mm
The height of object is given as 4 mm.Let the object height is denoted as -
The transverse measurement above the principal axis is positive.hence object height will be positive.
As per the question we are asked to calculate the image height.Let the image height is denoted as -
The transverse magnification m of for spherical mirror is given as below-
Putting the values of respective quantities we will get-
Here negative sign indicates that the image is below the principal axis i.e the image is inverted.
Hence option D is right.