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zhuklara [117]
3 years ago
10

The Sun’s surface temperature is about 5800 K and its spectrum peaks at 5000 Å. An O-type star’s surface temperature may be 40,0

00 K. (a) According to Wien’s law, at what wavelength does its spectrum peak? (b) In what part of the spectrum might that peak be? (c) Can the peak be observed with the Keck telescopes on Maunakea in Hawaii? Explain.
Physics
1 answer:
vova2212 [387]3 years ago
7 0

Answer:

Part a)

\lambda_2 = 725 A^o

Part b)

This range of wavelength exist in the region of X rays

So correct answer will be X Rays

Part c)

No it is not visible because this energy can not travel to large distance

Explanation:

Part a)

As per Wein's law we know that

\lambda_1T_1 = \lambda_2 T_2

so we know that

\lambda_1 = 5000A^o

T_1 = 5800 K

T_2 = 40,000 K

now we have

\lambda_2 = \frac{5000 \times 5800}{40,000}

\lambda_2 = 725 A^o

Part b)

This range of wavelength exist in the region of X rays

So correct answer will be X Rays

Part c)

No it is not visible because this energy can not travel to large distance

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a net force of 219 N is exterted on a rock. the rock has an acceleration of 3m/s^2 due to this force. what is the mass of the ro
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Answer:

<h2>73 kg</h2>

Explanation:

The mass of the object can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{219}{3}  \\

We have the final answer as

<h3>73 kg</h3>

Hope this helps you

6 0
3 years ago
Question 2 10
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2 years ago
A 70.0 kg sprinter starts a race with an acceleration of 1.60 m/s^2, What is the net external force (in N) on him? (Enter the ma
Ierofanga [76]

Answer:

External force on him will be 112 N

Explanation:

We have given the mass of the sprinter m =70 kg

Acceleration of the sprinter a=1.6m/sec^2

We have to find the net external force

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Force is dependent on the mass and acceleration

So F=70\times 1.6=112 N

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6 0
3 years ago
Use Newton’s Universal Law of Gravitation to calculate the magnitude of the gravitational force between a 200 kg refrigerator an
expeople1 [14]

Answer:

3.735×10⁻⁶ N

Explanation:

From newton' s law of universal gravitation,

F = Gmm'/r² .............................. Equation 1

Where F = Gravitational force between the person and the refrigerator, m = mass of the person, m' = mass of the refrigerator, r = distance between the person and the refrigerator. G = gravitational universal constant.

Given: m = 70 kg, m' = 200 kg, r = 0.5 m

Constant: G = 6.67×10⁻¹¹ Nm²/kg².

F = (6.67×10⁻¹¹×70×200)/0.5²

F = 93380×10⁻¹¹/0.25

F = 373520×10⁻¹¹

F = 3.735×10⁻⁶ N

Hence the force between the person and the refrigerator =  3.735×10⁻⁶ N

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