The net force on a 0.50-cm-diameter eardrum is mathematically given as
F= 0.76969 N
<h3>What is the net force on a 0.50-cm-diameter eardrum?</h3>
Generally, the equation for Pressure is mathematically given as
P = ρgh
Therefore
P= 1000*9.8*4
P= 39200 Pa
Where
A= pi*(0.005/2)^2
Generally, the equation for Net force is mathematically given as
F = PA
F= 39200 *( pi*(0.005/2)^2)
F= 0.76969 N
In conclusion, The net force is
F= 0.76969 N
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Answer:
distance = 3 + 4 = 7 mi
displacement is √(3² + 4²) = 5 mi
Explanation:
Answer:
We know that potential energy of a body;
= mass(m)× gravitational acceleration(g) × height(h)
Lets find out the mass of the body
P.E. = mgh
=> 6500J = mass × 9.8m/s^2 × 12m
=>6500J = mass × ( 9.8 × 12 ) × ( m/s^2 × m)
=> 6500 Nm = m × 117.6 × m^2 / s^2
=> 6500/117.6 Ns^2/m = mass [°.° Ns^2/m = kg]
=> 55.272 Kg = mass
Therefore the mass of the body = 55.272 kg ~ <em>6</em><em>0</em><em> </em><em>k</em><em>g</em><em> </em>(Ans)
Hope it helps you
The answer that you are looking for is D.
Answer:
By the information given, I am not sure how the event has played out. However, using common knowledge, I can give a scenario of how it may play out.
When removing the first block (the foundation), gravity will pull the other blocks down, as the strength of gravity exceeds that of the strength of air holding it up. This means that all the blocks on top would fall.
By definition of Newton's 1st - 3rd laws, the blocks would not move unless a force is given to it (i.e., removing the bottom block, which causes gravity). Gravity would pull the other blocks downwards. This would lead to the falling of the stack of blocks.
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