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ipn [44]
3 years ago
10

How to work out this problem??

Physics
1 answer:
tensa zangetsu [6.8K]3 years ago
8 0
Veo en youtube es buena explicacion hablame por mensaje y te doy el link
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Help????????????????????
Elan Coil [88]
A. Six electrons
B. six protons
C. they are composed of two up quarks and one down quark.
5 0
3 years ago
A ball is rolled at an initial speed of 5 m/s and finishes a certain distance at a speed of 7 m/s. if the ball rolled for 9 seco
Setler79 [48]

Answer:

The ball rolled a distance of 54 m.

Explanation:

Given:

Initial velocity of the ball is, u=5\ m/s

Final velocity of the ball is, v=7\ m/s

Time for rolling is, t=9\ s

The distance of rolling is, S=?

First, let us find the acceleration of the ball using Newton's equation of motion as:

v=u+at\\a=\frac{v-u}{t}\\a=\frac{7-5}{9}=\frac{2}{9}\ m/s^2

Now, displacement of the ball can be determined using the following equation of motion:

v^2=u^2+2aS

Rewriting the above in terms of 'S', we get

S=\frac{v^2-u^2}{2a}

Plug in the known values and solve for 'S'. This gives,

S=\frac{7^2-5^2}{2\times \frac{2}{9}}\\\\S=\frac{49-25}{\frac{4}{9}}\\\\S=\frac{9\times 24}{4}\\\\S=9\times 6=54\ m

Therefore, the ball rolled a distance of 54 m.

3 0
4 years ago
Energy of a wave is measured in terms of the wave's ?
Tamiku [17]
Energy refers to the speed.So u use the formula speed=wavelength×frequency
4 0
3 years ago
Read 2 more answers
Question: Why do both the moon and the earth pull on the spaceship the entire time? Why must you be closer to the moon before th
Ira Lisetskai [31]
-- There's no limit to the distance of gravitational forces. 
There's gravitational force between Pluto and the lint in your
pocket ... not much, but it's there, and it can be calculated.

So there's ALWAYS gravitational force between the Earth and the
spaceship, AND ALSO between the Moon and the spaceship. 
Even before it's ever launched !

-- The Earth has about 80 times as much mass as the Moon has,
so you have to be much closer to the Moon before the gravitational
forces in each direction are equal.
8 0
3 years ago
1. A 75 kg rock climber hangs from a cliff.
aliina [53]

The free body diagram of the rock comprises the tension on the rope acting upwards and the weight of the rock acting downwards.

The tension on the supporting rope is 735 N.

The given parameters;

  • <em>mass of the rock, m = 75 kg</em>

(a) The free body diagram of the rock is presented as follows;

                                                 ↑ T

                                                 Ο

                                                 ↓ W

Where;

<em>T is the tension on the supporting rope</em>

<em>W is the weight of the rock</em>

(b) The tension on the rope is calculated as follows;

T = W

T = mg

T = 75 x 9.8

T = 735 N

Thus, the free body diagram of the rock comprises the tension on the rope acting upwards and the weight of the rock acting downwards. The tension on the supporting rope is 735 N.

Learn more here: brainly.com/question/11599933

6 0
3 years ago
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