Answer:
The Answer is B because the material the object is made of, the position, or the color have absolutely nothing to do with gravitational potential energy
Answer:
Number of revolutions=1.532 revolutions
Explanation:
Given data
Distance s=8.0 m
Angular speed a=1.2 rev/s
To find
Number of revolutions
Solution
From the equation of simple motion we not that
![S=ut+1/2gt^{2}\\ where\\u=0\\So\\8.0m=0+(1/2)(9.8m/s^{2} )t^{2}\\ t^{2}=\frac{8.0m}{0.5*9.8m/s^{2} } \\ t^{2}=1.63\\t=\sqrt{1.63} \\t=1.28s](https://tex.z-dn.net/?f=S%3Dut%2B1%2F2gt%5E%7B2%7D%5C%5C%20where%5C%5Cu%3D0%5C%5CSo%5C%5C8.0m%3D0%2B%281%2F2%29%289.8m%2Fs%5E%7B2%7D%20%29t%5E%7B2%7D%5C%5C%20t%5E%7B2%7D%3D%5Cfrac%7B8.0m%7D%7B0.5%2A9.8m%2Fs%5E%7B2%7D%20%7D%20%5C%5C%20t%5E%7B2%7D%3D1.63%5C%5Ct%3D%5Csqrt%7B1.63%7D%20%5C%5Ct%3D1.28s)
So for the number of revolutions she makes is given as
![n=a*t\\n=(1.2rev/s)(1.28s)\\n=1.532revolutions](https://tex.z-dn.net/?f=n%3Da%2At%5C%5Cn%3D%281.2rev%2Fs%29%281.28s%29%5C%5Cn%3D1.532revolutions)
Answer: ![0.75\ cm](https://tex.z-dn.net/?f=0.75%5C%20cm)
Explanation:
Given
Wavelength of light ![\lambda=500\ nm](https://tex.z-dn.net/?f=%5Clambda%3D500%5C%20nm)
Screen is
away
Distance between two adjacent bright fringe is ![\Delta y=\dfrac{\lambda D}{d}](https://tex.z-dn.net/?f=%5CDelta%20y%3D%5Cdfrac%7B%5Clambda%20D%7D%7Bd%7D)
When same experiment done in water, wavelength reduce to ![\dfrac{\lambda }{\mu}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Clambda%20%7D%7B%5Cmu%7D)
So, the distance between the two adjacent bright fringe is ![\Delta y'=\dfrac{\lambda D}{\mu d}](https://tex.z-dn.net/?f=%5CDelta%20y%27%3D%5Cdfrac%7B%5Clambda%20D%7D%7B%5Cmu%20d%7D)
Keeping other factor same, distance becomes
![\Rightarrow \dfrac{1}{\frac{4}{3}}=\dfrac{3}{4}\quad \text{Refractive index of water is }\dfrac{4}{3}\\\\\Rightarrow 0.75\ cm](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cdfrac%7B1%7D%7B%5Cfrac%7B4%7D%7B3%7D%7D%3D%5Cdfrac%7B3%7D%7B4%7D%5Cquad%20%5Ctext%7BRefractive%20index%20of%20water%20is%20%7D%5Cdfrac%7B4%7D%7B3%7D%5C%5C%5C%5C%5CRightarrow%200.75%5C%20cm)