How many grams of caf2 would be needed to produce 8.41×10-1 moles of f2?
1 answer:
Answer: 65.7 grams
Explanation:
1) ratio
Since 1 mole of CaF2 contains 1 mol of F2, the ratio is:
1 mol CaF2 : 1 mol F2
2) So, to produce 8.41 * 10^ -1` mol of F2 you need the same number of moles of CaF2.
3) use the formula:
mass in grams = molar mass * number of moles
molar mass of CaF2 = 40.1 g/mol + 2 * 19.0 g/mol = 78.1 g/mol
mass in grams = 78.1 g/mol * 8.41 * 10^ -1 mol = 65.7 grams
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