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Murljashka [212]
4 years ago
8

If 6.02*10^23 molecules of ammonia react with 12.04*10^23 molecules of hydrogen chloride, how many molecules are in the reaction

vessel when the reaction is complete
Chemistry
1 answer:
Helen [10]4 years ago
3 0

Answer:

18.06 × 10²³ molecules

Explanation:

Add the two amounts of molecules together.

6.02 × 10²³  +  12.04 × 10²³  =  18.06 × 10²³

You will have 18.06 × 10²³ molecules in the vessel when the reaction is complete.  This is because of the Law of Conservation of Mass.  Mass is neither created nor destroyed in chemical reactions.  You will have the exact number of molecules in the reaction vessel as you did in the beginning.  The types of molecules may change, but the number will stay the same.

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Convert 5.0 x 1027 r.p. of copper to moles of copper.
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In the molar volume of a gas lab, a student
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3 years ago
A sample of sulfur dioxide occupies a volume of 562 mL at 45.° C and
yanalaym [24]

Answer:

3.43 L

Explanation:

By the ideal gas law, when there is a state change, the quantities can be calculated by:

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3 0
3 years ago
How many moles are in 250 grams of tungsten (W)? * 4.4x10^23 moles 4.2x10^23 moles 0.7 moles 1.4 moles
kvasek [131]

Ans: 1.4 moles

<u>Given:</u>

Mass of tungsten = 250 g

<u>To determine:</u>

Moles of Tungsten

<u>Explanation:</u>

# moles of a given substance = Mass of the substance in grams/molar mass (g.mol-1)

Atomic mass of W = 184 g.mol-1

# moles of W = 250 g/184 g.mol-1 = 1.359 moles

3 0
3 years ago
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