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Dimas [21]
2 years ago
8

4. Substances that existed before mixing-still exist-after substances-are-mixed----

Chemistry
1 answer:
pantera1 [17]2 years ago
5 0
False; Because when 2 substances are mixed another substance is created.
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How much energy is released when 0.40 mol C6H6(g) completely reacts with oxygen?
Vsevolod [243]
 <span>This question asksyou to apply Hess's law. 
You have to look for how to add up all the reaction so that you get the net equation as the combustion for benzene. The net reaction should look something like C6H6(l)+ O2 (g)-->CO2(g) +H2O(l). So, you need to add up the reaction in a way so that you can cancel H2 and C. 
multiply 2 H2(g) + O2 (g) --> 2H2O(l) delta H= -572 kJ by 3 
multiply C(s) + O2(g) --> CO2(g) delta H= -394 kJ by 12 
multiply 6C(s) + 3 H2(g) --> C6H6(l) delta H= +49 kJ by 2 after reversing the equation. 
Then, 
6 H2(g) + 3O2 (g) --> 6H2O(l) delta H= -1716 kJ 
12C(s) + 12O2(g) --> 12CO2(g) delta H= -4728 kJ 
2C6H6(l) --> 12 C(s) + 6 H2(g) delta H= - 98 kJ 
______________________________________... 
2C6H6(l) + 16O2 (g)-->12CO2(g) + 6H2O(l) delta H= - 6542 kJ 
I hope this helps and my answer is right.</span>
4 0
3 years ago
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Is PO4^-3 polar, non-polar, or ionic?
Gala2k [10]
The answer is PO4^-3 is non-polar.
8 0
3 years ago
Does vinegar conduct? yes or no
uranmaximum [27]
Im guessing and i think the answer is yes.
8 0
2 years ago
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An atom X has atomic number 15,it accepts 3 electrons in other to become stable,determine the,*Number of protons of the atom. *D
Lisa [10]

Answer:

15 protons

8 electrons in valence shell after accepting 3 electrons

Neutral/no charge before accepting 3 electrons

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4 0
2 years ago
30 pts! Sodium and water react according to the following equation. If 31.5g of sodium are added to excess water, how many liter
mihalych1998 [28]
First, calculate the number of moles of sodium present with the given mass,

              31.5 g of sodium x (1 mol sodium/ 23 g sodium) = 1.37 mol sodium

It is given in the equation that for every 2mols of sodium, one mol of H2 is produced.

           mols of H2 = (1.37 mols sodium)(1 mol H2/ 2 mols sodium)
                  mols of H2 = 0.685 mols H2

Then, at STP, 1 mol of gas = 22.4 L.
                
                 volume of H2 = (0.685 mols H2)(22.4 L / 1 mol)
                     volume of H2 = 15.34 L

Answer: 15.34 L
3 0
3 years ago
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