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Keith_Richards [23]
2 years ago
8

What can you conclude about the relationship between height and energy?​

Chemistry
1 answer:
Bas_tet [7]2 years ago
7 0

Answer:

Since the gravitational potential energy of an object is directly proportional to its height above the zero position, a doubling of the height will result in a doubling of the gravitational potential energy. A tripling of the height will result in a tripling of the gravitational potential energy.

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What is an effect of gravity on objects on the surface of Earth? Check all that apply.
Flauer [41]

Answer: The correct statements are:

  • Objects “fall” toward the center of Earth.
  • Objects accelerate at a rate of 9.8 m/s each second.
  • Objects are pulled by Earth more strongly than they pull on Earth.

Explanation:

The gravity of the earth is the force which attracts the object to the center of the earth. When the any object with mass falls under the action of the gravity attains the acceleration of 9.8 m/s^2.

  • Objects “fall” toward the center of Earth.
  • Objects accelerate at a rate of 9.8 m/s each second.
  • Objects are pulled by Earth more strongly than they pull on Earth.
9 0
3 years ago
Read 2 more answers
A 12-liter tank contains helium gas pressurized to 160 \rm atm.How many 3-liter balloons could the 12-L helium tank fill? Keep i
Vikentia [17]

Answer:

636 balloons

Explanation:

If we assume that helium gas follows an ideal gas behaviour, we can use the ideal gas law to solve this problem as follows:

  1. We consider two different states, the initial given by the conditions of the problem statement and the final, when the tank reaches atmospheric pressure and it's no longer able to fill balloons:P_{1}=160 atm\\V_{1}=12 L\\P_{2}=1 atm\\V_{2}= ?
  2. To find out what would be this volume 2, we use the Boyle's Law: P_{1}V_{1}=P_{2}V_{2}\\V_{2}=\frac{P_{1}V_{1}}{P_{2}} \\V_{2}=\frac{160 atm \times 12L}{1 atm}\\V_{2}=1920 L
  3. Now we find the available volume to fill the balloons by substracting both, volume 2 and volume 1: V_{b}=V_{2}-V_{1}=1920L-12L=1908 L
  4. Finally, we determine the quantity of ballons by dividing that available volume between the volume of each ballon:B=\frac{1908L}{3L} =636 balloons
8 0
2 years ago
Which one is the answer... a, b, or c?
jenyasd209 [6]
The answer for this one is a
8 0
3 years ago
A city continuously disposes of effluent from a wastewater treatment plant into a river. The minimum flow in the river is 130 m3
Vera_Pavlovna [14]

Answer:

2.54\ \text{mg/L}

Explanation:

C = Allowable concentration = 1.1 mg/L

Q_1 = Flow rate of river = 130\ \text{m}^/\text{s}

Q_2 = Discharge from plant = 37\ \text{m}^3/\text{s}

C_1 = Background concentration = 0.69 mg/L

C_2 = Maximum concentration that of the pollutant

The concentration of the mixture will be

C=\dfrac{Q_1C_1+Q_2C_2}{Q_1+Q_2}\\\Rightarrow C_2=\dfrac{C(Q_1+Q_2)-Q_1C_1}{Q_2}\\\Rightarrow C_2=\dfrac{1.1(130+37)-130\times 0.69}{37}\\\Rightarrow C_2=2.54\ \text{mg/L}

The maximum concentration that of the pollutant (in mg/L) that can be safely discharged from the wastewater treatment plant is 2.54\ \text{mg/L}.

6 0
2 years ago
A gas occupies a 1.5 L container at 25 degrees Celsius and 2.0 atm. If the gas is transferred to a 3.0 L container at the same t
harkovskaia [24]

To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

P1V1 =P2V2

P2 = P1 x V1 / V2

P2 = 2.0 x 1.5 / 3

<span>P2 = 1 atm</span>

4 0
3 years ago
Read 2 more answers
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