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3 years ago

Which two particles are found in the nucleus of an atom?

2 answers:

7 0

Answer:

Protons and neutrons are found in the nucleus of the atom.

Explanation:

Protons and neutrons are found in the nucleus of the atom, while electrons are outside of the nucleus.

max2010maxim [7]3 years ago

4 0

Answer:

Protons and neutrons

Explanation:

Nucleus is the central dense part of the nucleus and consists of most of the mass of an atom.

An atom has three subatomic particles:

Electrons
Protons
Neutrons

Electrons are negatively charged subatomic particles, protons are positively charged and neutrons are neutral.

Electrons are present in the energy shells outside to the nucleus and revolve around it.

Protons and neutrons are present in nucleus.

Number of protons and neutrons present in the nucleus together called mass number or atomic mass.

Therefore,

Atomic mass = No. of protons + No. of neutrons

Number of protons present in the nucleus is same as the number of electrons present outside nucleus.

Therefore,

No. of protons = No. of electrons = Atomic number

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Nitrogen monoxide, NO, reacts with hydrogen, H₂, according to the following equation.

Anvisha [2.4K]

Answer : The rate law for the overall reaction is, $Rate=k[NO]^2[H_2]$

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

As we are given the mechanism for the reaction :

Step 1 : $2NO+H_2\rightarrow N_2+H_2O_2$ (slow)

Step 2 : $H_2O_2+H_2\rightarrow 2H_2O$ (fast)

Overall reaction : $2NO+2H_2\rightarrow N_2+2H_2O$

The rate law expression for overall reaction should be in terms of $NO\text{ and }H_2$ .

As we know that the slow step is the rate determining step. So,

The slow step reaction is,

$2NO+H_2\rightarrow N_2+H_2O_2$

The expression of rate law for this reaction will be,

$Rate=k[NO]^2[H_2]$

Hence, the rate law for the overall reaction is, $Rate=k[NO]^2[H_2]$

8 0

3 years ago

What are the products of any combustion reaction involving a hydrocarbon

sweet [91]

Answer:

<em><u>The products of the combustion of hydrocarbons are carbon dioxide and water. Many hydrocarbons are used as fuel because their combustion releases very large amounts of heat energy.</u></em>

4 0

2 years ago

Read 2 more answers

Which statement explains the relationship between evaportion

Dimas [21]

Is there answer choices ?

5 0

3 years ago

Many oxidation-reduction reactions can be balanced by inspection. Try to balance the following reactions by inspection. In each

Phoenix [80]

Answer:

Balanced reaction: C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)

Reduced: O₂

Oxidized : C₃H₈

Explanation:

For the given reaction:

C₃H₈(g) + O₂(g) → CO₂(g) + H₂O(l)

In the reactants, there are 3 C, and in the products only one, so we multiply CO₂ by 3:

C₃H₈(g) + O₂(g) → 3CO₂(g) + H₂O(l)

In the reactants, there are 8 H, and in the products, there are 2 H, so we multiply H₂O by 4:

C₃H₈(g) + O₂(g) → 3CO₂(g) + 4H₂O(l)

In the reactants are 2 O, and in the products 10 O, so we multiply O₂ by 5:

C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)

The reaction is balanced.

Let's identify the oxidation number (Nox) of the elements in each compound.

C₃H₈:

H has fix Nox equal to +1, and the molecule is neutral, so, calling x the Nox of C:

3x + 8 = 0

3x = -8

x = -8/3

O₂:

Because is a pure compound, the Nox of O is 0.

CO₂:

The Nox of O is fix equal to -2, and the molecule is neutral, so, calling x the Nox of C:

2x -4 = 0

2x = 4

x = +2

H₂O:

The Nox of H and O are fixed, respectively, +1 and -2.

So, the carbon in C₃H₈ is oxidized because its Nox is increasing, and oxygen in O₂ is reduced because its Nox is decreasing.

6 0

3 years ago

1. A 67 kg water-skier is being pulled by a speedboat. The force causes her to accelerate at 3.8

Alborosie

Answer:

254.6N

Explanation:

F=ma

F=67×3.8

F=254.6N

4 0

3 years ago