Sally travels by car from one city to another. She drives for 26.0 min at 83.0 km/h, 52.0 min at 41.0 km/h, and 45.0 min at 60.0
1 answer:
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The question seems incomplete. The complete text is:
a)What is the angular displacement of the wheel between t = 5 s and t = 15 s
b)What is the angular velocity of the wheel at 15 s
And it refers to the attached figure.
a) 25 rad
The graph shown represent the angular position of the wheel at different times.
Therefore, we can simply calculate the angular displacement between two times by calculating the difference between the angular position at t2 and the angular position at t1.
At , the angular position from the graph is
At , the angular position from the graph is
Therefore, the angular displacement is
2) -5.0 rad/s
For a angular displacement vs time graph, the angular velocity at any time is simply equal to the slope of the curve at that time.
Here we want to calculate the angular velocity at t = 15 s, so we have to calculate the slope at that time.
By noting that the slope is constant in the last part of the motion, we find that the slope between 10 s and 20 s is:
This slope is constant between 10 s and 20 s, so the angular velocity of the wheel at t = 15 s
Answer:
Magnitude of avg velocity,
Given:
Constant speed of train, v = 79 km/h
Time taken in East direction, t = 27 min =
Angle,
Time taken in east of due North direction, t' = 29 min =
Time taken in west direction, t'' = 37 min =
Solution:
Now, the displacement, 's' in east direction is given by:
Displacement in east of due North for 29.0 min is given by:
Now, displacement in the west direction for 37 min:
Now, the overall displacement,
(a) Now, average velocity, is given:
Magnitude of avg velocity is given by:
(b) angle can be calculated as: