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spin [16.1K]
3 years ago
10

ANOTHER PHYSICS QUESTION PLEASE HELP!

Physics
1 answer:
Sergio039 [100]3 years ago
5 0
Answer


= 60


Hope it helps:)
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Typically, business software technologies are complex, and software strenuous. Business software applications are also often upgraded for changes in business goals or procedures. Real-time systems usually require a lot of hardware components that are quite difficult to change and cannot be upgraded Usually, actual-time safety critical systems that required to be built based on well-planned processes.

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What is the most common grip used in racket sports?
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The continental ...........
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An object is placed a great distance from a concave (converging) mirror. Where will light from the object be collected?
AveGali [126]

Answer: at the center of curvature of the mirror on the same side of the mirror as the object

A concave mirror has a reflective surface that is curved inwards.  This type of mirrors reflects the light making it converge in a focal point, therefore they are used to focus the light.

This occurs because the light is reflected with different angles, since the normal to the surface varies from one point to another of the mirror.

Nevertheless, it is important to note the object must be within the radius of curvature of the mirror.

In addition, it is important to state clear the following:

-If the object is at a distance greater than the focal distance, a <u>real</u> and <u>inverted image</u> is formed that may be greater or less than the object.

-If the object is at a distance smaller than the focal distance, a <u>virtual</u> image is formed, <u>right and larger than the object</u>.

In this case the object is placed a great distance (it can be said at infinite) from the concave mirror, hence the image formed will be real, inverted and smaller than the object.

When we say <u>real</u>, it means the image is formed in the same side of the mirror as the object and the image can be seen on a screen.

5 0
3 years ago
Read 2 more answers
One airplane is approaching an airport from the north at 181 kn/hr. A second airplane approaches from the east at 278 km/hr. Fin
umka2103 [35]

Answer:

The value  is  \frac{dR}{dt} =  -286.2 \  km/hr

Explanation:

From the question we are told that  

   The speed of the airplane from the north is \frac{dN}{dt}  =  -181 \  km /hr

The negative sign is because the direction is towards the south

  The speed of the airplane from the east is  \frac{dE}{dt}  =  -278 \  km/hr

The negative sign is because the direction is towards the west

   The distance of the southbound plane from the airport is  N  =  30 \  km

   The distance of the westbound plane is  E =  15 \  km

Generally the distance between the plane is mathematically represented using Pythagoras theorem  as

    R^2  = N^2 + E^2

Next differentiate implicitly this equation to obtain the rate at which the distance between the planes changes

So

     2R\frac{dR}{dt} =  2N \frac{dN}{dt} +   2E\frac{dE}{dt}

Here

     R = \sqrt{N^2 + E^2}

=>    R = \sqrt{30^2 + 15^2}

=>    R = \sqrt{30^2 + 15^2}

=>    R =33.54 \ m

    2(33.54) * \frac{dR}{dt} =  2( 30)*(-181)  +   2*15*(-278)

=>   67.08 * \frac{dR}{dt} =  -19200

=>   \frac{dR}{dt} =  -286.2 \  km/hr

4 0
4 years ago
A standing wave with 5 loops is created on a string that is 0.75 m long. If the
Alex

wave velocity = frequency × wavelength

300 = frequency × 0.75

Frequency = 300÷0.75 = 400 HZ

6 0
3 years ago
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