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4 years ago

Parallax of the stars is created by

2 answers:

5 0

The parallax of the stars is created by the different location of Earth in it's orbit. When the earth moves from one side to the other (every 6 months) the distances of the stars change.

k0ka [10]4 years ago

4 0

Parallax of the stars is created by :
B. Different locations of Earth in its orbit
Parallax refer to the position of an object (in this case, a star) that will look different if we view it from different positions

hope this helps

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What is the cause of weathering

iren2701 [21]

Plant and animal life, atmosphere and water are the major causes of weathering .

5 0

4 years ago

Read 2 more answers

A solid sphere, solid cylinder, and a hollow pipe all have equal masses and radii. If the three of them are released simultaneou

Roman55 [17]

Answer:

The solid sphere will reach the bottom first.

Explanation:

In order to develop this problem and give it a correct solution, it is necessary to collect the concepts related to energy conservation. To apply this concept, we first highlight the importance of conserving energy so we will match the final and initial energies. Once this value has been obtained, we will concentrate on finding the speed, and solving what is related to the Inertia.

In this way we know that,

$\Delta KE = - \Delta PE$

$KE_t + KE_r = mgh$

We know as well that the lineal and angular energy are given by,

$KE_r = \frac{1}{2}I\omega^2$

And the tangential kinetic energy as

$KE_t = \frac{1}{2} mv^2$

Where $\omega = \frac{v}{R}$

Replacing

$\frac{1}{2}mv^2 + \frac{1}{2}I\frac{v}{R} = mgh$

Re-arrange for v,

$v=\sqrt{\frac{2mgh}{m+I/R^2}}$

We have here three different objects: solid cylinder, hollow pipe and solid sphere. We need the moment inertia of this objects and replace in the previous equation found, then,

For hollow pipe:

$I_{hp}=mR^2$

$v_{hp}=\sqrt{\frac{2mgh}{m+(mR^2)/R^2}}$

$v_{hp}=\sqrt{\frac{2mgh}{m+m)}$

$v_{hp}=\sqrt{gh}$

For solid cylinder:

$I_{sc}=\frac{1}{2}mR^2$

$v_{sc}=\sqrt{\frac{2mgh}{m+(1/2mR^2)/R^2}}$

$v_{sc}=\sqrt{\frac{2mgh}{m+1/2m}}$

$v_{sc}=\sqrt{\frac{3}{4}gh}$

For solid sphere,

$I_{ss}=\frac{2}{5}mR^2$

$v_{ss}=\sqrt{\frac{2mgh}{m+(2/5mR^2)/R^2}}$

$v_{ss}=\sqrt{\frac{2mgh}{m+2/5m}}$

$v_{ss}=\sqrt{\frac{10}{7}gh}$

Then comparing the speed of the three objects we have:

$v_{hp}$

$\sqrt{gh}$

3 0

4 years ago

9. A ball is thrown straight up with an initial speed of 30 m/s. How long will it take to reach the top of its trajectory, and h

ziro4ka [17]

Answer:

1.) Time t = 3.1 seconds

2.) Height h = 46 metres

Explanation:

given that the initial velocity U = 30 m/s

At the top of the trajectory, the final velocity V = 0

Using first equation of motion

V = U - gt

g is negative 9.81m/^2 as the object is going against the gravity.

Substitute all the parameters into the formula

0 = 30 - 9.81t

9.81t = 30

Make t the subject of formula

t = 30/9.81

t = 3.058 seconds

t = 3.1 seconds approximately

Therefore, it will take 3.1 seconds to reach to reach the top of its trajectory.

2.) The height it will go can be calculated by using second equation of motion

h = ut - 1/2gt^2

Substitutes U, g and t into the formula

h = 30(3.1) - 1/2 × 9.8 × 3.1^2

h = 93 - 47.089

h = 45.911 m

It will go 46 metres approximately high.

6 0

3 years ago

Find the displacement if the velocity is 100 km to the east, time=3 h

scoray [572]

T = 3 h = 3 x 3600s = 10800s
d = 100 x 10800 = 1080000km to The east.

8 0

4 years ago

Two spectators at a soccer game in Montjuic Stadium see, and a moment later hear, the ball being kicked on the playing field. Th

NikAS [45]

Answer:

a) 68.943 m

b) 41.846 m

c) 80.648 m

Explanation:

Given:

Delay in time for spectator A, t₁ = 0.201 s

Delay in time for spectator B, t₂ = 0.122 s

the delay in sound heard is the due to the distance being traveled by the sound from the kicker to the spectator

thus,

a) Distance of the kicker from A,

d₁ = speed of sound × time taken

d₁ = 343 m/s × 0.201 s = 68.943 m

b) Distance of the kicker from B,

d₂ = speed of sound × time taken

d₂ = 343 m/s × 0.122 = 41.846 m

c) Since the angle between the two spectators for the player is 90°

thus, a right angles triangle is formed.

where, the distance between the spectators is the hypotenuses (s) of the so formed triangle

Therefore,

s² = d₁² + d₂²

on substituting the values, we get

s² = 68.943² + 41.846²

s² = 6504.22

s = √6504.22

s = 80.648 m

hence, the distance between the spectators is 80.648 m

3 0

3 years ago