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bagirrra123 [75]
3 years ago
9

The density of an object is defined as mass per unit volume. Mathematically we write that:

Chemistry
2 answers:
babunello [35]3 years ago
8 0
M=DxV V=M/D
(answer limit etcetcetc)))))
zhuklara [117]3 years ago
7 0
For the mass M= D x V

for the volume V= M/D
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What is the difference between an onion cell and the cheek cell
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The difference I think is the fact one has DNA and the other doesn't.
4 0
4 years ago
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What is the concentration (M) of CH3OH in a solution prepared by dissolving 11.7 g of CH3OH in sufficient water to give exactly
Andrej [43]

Answer:

3.65~M

Explanation:

We have to remember the <u>molarity equation</u>:

M=\frac{mol}{L}

So, we have to calculate "mol" and "L". The total volume is 100 mL. So, we can do the <u>conversion</u>:

100~mL\frac{1~L}{1000~mL}=~0.1~L

Now we can calculate the moles. For this we have to calculate the <u>molar mass</u>:

O: 16 g/mol

H: 1 g/mol

C: 12 g/mol

(16*1)+(1*4)+(12*1)=32~g/mol

With the molar mass value we can <u>calculate the number of moles</u>:

1.7~g~of~CH_3OH\frac{1~mol~CH_3OH}{32~g~of~CH_3OH}=0.365~mol~CH_3OH

Finally, we can <u>calculate the molarity</u>:

M=\frac{0.365~mol~CH_3OH}{0.1~L}=3.65~M

I hope it helps!

7 0
3 years ago
Calculate the pH for each case in the titration of 50.0 mL of 0.230 M HClO ( aq ) 0.230 M HClO(aq) with 0.230 M KOH ( aq ) . 0.2
Vikentia [17]

Answer:

pH before addition of KOH = 4.03

pH after addition of 25 ml KOH = 7.40

pH after addition of 30 ml KOH = 7.57

pH after addition of 40 ml KOH = 8.00

pH after addition of 50 ml KOH = 10.22

pH after addition 0f 60 ml KOH = 12.3

Explanation:

pH of each case in the titration given below

(6) After addition of 60 ml KOH

Since addition of 10 ml extra KOH is added after netralisation point.

Concentration of solution after addition 60 ml KOH is calculated by

M₁V₁ = M₂V₂

or, 0.23 x 10 = (50 + 60)ml x M₂

or M₂ = 0.03 Molar

so, concentration of KOH = 0.03 molar

                               [OH⁻] = 0.03 molar

                                 pOH = 0.657

                                  pH = 14 - 0.657 = 13.34

5 0
4 years ago
CAN YOU HELP ME WITH THIS?????????????????????????????????????? ????????????????????????????????????????????????????????????????
maria [59]

PV=nRT  

P = 85.0 x 10^3 Pa  

T = 273 + 20 = 293 K  

n = 2.0 moles  

R = 8.314 m3. pa / mol .K  

V = 2.0 x 293 x 8.314 / 85.0x10^3 =  0.195623529 m^3

6 0
3 years ago
How many formula units are 113.5 grams of Ca(OH)2
Sav [38]

Answer:

Molecular Formula Ca(OH)2 or CaH2O2

Synonyms CALCIUM HYDROXIDE 1305-62-0 Slaked lime Hydrated lime Ca(OH)2

Molecular Weight 74.09 g/mol

Component Compounds CID 962 (Water) CID 5460341 (Calcium)

Explanation:

8 0
3 years ago
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