The compound MgCl2(aq) is ionic which will have the releasing of 2 Cl⁻ ions ions in water for every molecule of MgCl2 that dissolves.
MgCl2(s) --> Mg+(aq) + 2 Cl⁻(aq)
[Cl⁻] = 0.87 mol MgCl2/1L × 2 mol Cl⁻ / 1 mol MgCl2 = 1.7 M
The answer to this question is [Cl⁻] = 1.7 M
Answer:
35.36 g
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
8Fe + S₈ —> 8FeS
Next, we shall determine the mass of Fe that reacted and the mass of FeS produced from the balanced equation. This can be obtained as follow:
Molar mass of Fe = 56 g/mol
Mass of Fe from the balanced equation = 8 × 56 = 448 g
Molar mass of FeS = 56 + 32 = 88 g/mol
Mass of FeS from the balanced equation = 8 × 88 = 704 g
SUMMARY:
From the balanced equation above,
448 g of Fe reacted to produce 704 g of FeS.
Finally, we shall determine the theoretical yield of FeS as follow:
From the balanced equation above,
448 g of Fe reacted to produce 704 g of FeS.
Therefore, 22.5 g of Fe will react to produce = (22.5 × 704)/448 = 35.36 g of FeS.
Thus, the theoretical yield of FeS is 35.36 g
The thing you MUST do FIRST is look for any H's, O's, or F's in the equation
1)any element just by itself not in a compound, their oxidation number is 0
ex: H2's oxidation number is 0
ex: Ag: oxidation number is 0 if its just something like Ag + BLA = LALA
2) the oxidation number of H is always +1, unless its just by itself (see #1)
3) the oxidation number of O is always -2, unless its just by itself (see #1)
4) the oxidation number of F is always -1, unless its just by itself (see#1)
ok so after you have written those oxidation numbers in rules 1-4 over each H, F, or O atom in the compound, you can look at the elements that we havent talked about yet
for example::::
N2O4
the oxidation number of O is -2.
since there are 4 O's, the charge is -8. now remember that N2O4 has to be neutral so the N2 must have a charge of +8
+8 divided by 2 = +4
N has an oxidation number of +4.
more rules:
5) the sum of oxidation numbers in a compound add up to 0 (when multiplied by the subscripts!!!) (see above example)
6) the sum of oxidation numbers in a polyatomic ion is the charge (for example, PO4 has a charge of (-3) so
oxidation # of O = -2. (there are 4 O's = -8 charge on that side ) P must have an oxidation number of 5. (-8+5= -3), and -3 is the total charge of the polyatomic ion
Charlidamelio is overrated
