The density of an object is defined as mass per unit volume. Mathematically we write that:
2 answers:
You might be interested in
Answer:
Explanation:
We have to remember the <u>molarity equation</u>:
So, we have to calculate "mol" and "L". The total volume is 100 mL. So, we can do the <u>conversion</u>:
Now we can calculate the moles. For this we have to calculate the <u>molar mass</u>:
O: 16 g/mol
H: 1 g/mol
C: 12 g/mol
With the molar mass value we can <u>calculate the number of moles</u>:
Finally, we can <u>calculate the molarity</u>:
I hope it helps!
Answer:
pH before addition of KOH = 4.03
pH after addition of 25 ml KOH = 7.40
pH after addition of 30 ml KOH = 7.57
pH after addition of 40 ml KOH = 8.00
pH after addition of 50 ml KOH = 10.22
pH after addition 0f 60 ml KOH = 12.3
Explanation:
pH of each case in the titration given below
(6) After addition of 60 ml KOH
Since addition of 10 ml extra KOH is added after netralisation point.
Concentration of solution after addition 60 ml KOH is calculated by
M₁V₁ = M₂V₂
or, 0.23 x 10 = (50 + 60)ml x M₂
or M₂ = 0.03 Molar
so, concentration of KOH = 0.03 molar
[OH⁻] = 0.03 molar
pOH = 0.657
pH = 14 - 0.657 = 13.34
