Question

When 0.105 mol propane, C3H8 is burned in an excess of oxygen, how many moles of oxygen are consumed? The products are carbon dioxide and water. You have to properly balance the equation before you can answer this question.
A) 0.420 mol O2
B) 0.525 mol O2
C) 0.875 mol O2
D) 0.905 mol O2
E) 0.975 mol O2

Answer 1

Answer: The amount of oxygen gas consumed is 0.525 moles

Explanation:

We are given:

Moles of propane burned = 0.150 moles

The chemical equation for the combustion of propane follows:

$C_3H_8+5O_2\rightarrow 3CO_2+4H_2O$

By Stoichiometry of the reaction:

1 mole of propane reacts with 5 moles of oxygen gas

So, 0.150 moles of propane will react with = $\frac{5}{1}\times 0.105=0.525mol$ of oxygen gas

Hence, the amount of oxygen gas consumed is 0.525 moles