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charle [14.2K]
3 years ago
11

Wait are these right?! PLS

Mathematics
2 answers:
Semmy [17]3 years ago
6 0

Answer:can u give me brainest its right

Step-by-step explanation:

Korolek [52]3 years ago
5 0

Answer:

yes they are good job

Step-by-step explanation:

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(14x-5)-(-3x+2)<br><br>A. 11x-3<br>B. 17x-7<br>C. 17x-3<br>D. 11x-7
Vladimir [108]
The answer would be B) 17x-7
4 0
3 years ago
135 students attended an assembly at Piper School. The student enrollment at the school is 180. What percentage of the students
soldier1979 [14.2K]
We know that the total number of students is 180, so 180 is the 100 precent of the students, now we can set up a proportion and solve

180/100=135/x

x=135 times 100 over 180
x=75%
8 0
3 years ago
Use lagrange multipliers to find the shortest distance, d, from the point (4, 0, −5 to the plane x y z = 1
Varvara68 [4.7K]
I assume there are some plus signs that aren't rendering for some reason, so that the plane should be x+y+z=1.

You're minimizing d(x,y,z)=\sqrt{(x-4)^2+y^2+(z+5)^2} subject to the constraint f(x,y,z)=x+y+z=1. Note that d(x,y,z) and d(x,y,z)^2 attain their extrema at the same values of x,y,z, so we'll be working with the squared distance to avoid working out some slightly more complicated partial derivatives later.

The Lagrangian is

L(x,y,z,\lambda)=(x-4)^2+y^2+(z+5)^2+\lambda(x+y+z-1)

Take your partial derivatives and set them equal to 0:

\begin{cases}\dfrac{\partial L}{\partial x}=2(x-4)+\lambda=0\\\\\dfrac{\partial L}{\partial y}=2y+\lambda=0\\\\\dfrac{\partial L}{\partial z}=2(z+5)+\lambda=0\\\\\dfrac{\partial L}{\partial\lambda}=x+y+z-1=0\end{cases}\implies\begin{cases}2x+\lambda=8\\2y+\lambda=0\\2z+\lambda=-10\\x+y+z=1\end{cases}

Adding the first three equations together yields

2x+2y+2z+3\lambda=2(x+y+z)+3\lambda=2+3\lambda=-2\implies \lambda=-\dfrac43

and plugging this into the first three equations, you find a critical point at (x,y,z)=\left(\dfrac{14}3,\dfrac23,-\dfrac{13}3\right).

The squared distance is then d\left(\dfrac{14}3,\dfrac23,-\dfrac{13}3\right)^2=\dfrac43, which means the shortest distance must be \sqrt{\dfrac43}=\dfrac2{\sqrt3}.
7 0
3 years ago
Help please thankssss
Bad White [126]
The answer to your question is r=6
8 0
1 year ago
How? Do you do this??
Gre4nikov [31]
X=5/2,x=2  
i cant explain it but if you got to symbolab.com and input the equation it will solve and show you the steps
5 0
3 years ago
Read 2 more answers
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