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3 years ago

Given sin x =.1234, find x in degrees.

1 answer:

7 0

You plug in the calculator sin−¹(.1234)
And it gives you 7.088
But since it asks you to round it your final answer would be:
7.1

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The range of the function

Naily [24]

Answer:

Range: {-4, 3, 5}

Step-by-step explanation:

The range of a function includes all the set of possible output, or y-values in a given data set of a function.

Thus, the range of the function, {(2, 3), (-3, 5), (6, -4)} includes 3, 5, and -4.

This can be written as:

Range: {-4, 3, 5}

7 0

3 years ago

Help now solve it but show your work too

marin [14]

Answer:

-1/6

Step-by-step explanation:

1/6-1/3

1/6-1×2/3×2

1/6-2/6

1-2/6

-1/6

5 0

3 years ago

Read 2 more answers

What are the solutions to the equation?<br><br> 3x^2+6x=45<br><br> Enter your answers in the boxes.

Gnoma [55]

x= 3,-5

hope this helps

5 0

4 years ago

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1/3 is the same as 1÷3 what is the exact quotient in decimal form of 1÷3

Oduvanchick [21]

Answer:

Here are two ways of writing it. I hope this helps!

3 0

3 years ago

Which are the solutions of x2 = –11x + 4? StartFraction negative 11 minus StartRoot 137 EndRoot Over 2 EndFraction comma StartFr

Marysya12 [62]

Answer:

$x_1=-\frac{11}{2}-\frac{\sqrt{137} }{2}\\\\x_2=-\frac{11}{2}+\frac{\sqrt{137} }{2}$

Step-by-step explanation:

Given the following quadratic equation:

$x^2 = -11x + 4$

The steps to solve it are:

1. Move the terms to one side of the equation:

$x^2+11x- 4=0$

2. Apply the Quadratic formula $x=\frac{-b\±\sqrt{b^2-4ac} }{2a}$ .

In this case we can identify that:

$a=1\\b=11\\c=-4$

Then, substituting these values into the Quadratic formula we get the following solutions:

$x=\frac{-11\±\sqrt{11^2-4(1)(-4)} }{2(1)}$

$x_1=-\frac{11}{2}-\frac{\sqrt{137} }{2}\\\\x_2=-\frac{11}{2}+\frac{\sqrt{137} }{2}$

3 0

4 years ago

Read 2 more answers