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kakasveta [241]
3 years ago
5

You know that for any , neither sin nor cos can be greater than 1. how can you explain this using the unit circle definitions of

sine and cosine
Mathematics
1 answer:
Feliz [49]3 years ago
4 0
In the unit circle the hypotenuse of the triangle formed  is equal to radius of circle , which = 1. The point on the circle formed by the intersection of the hypotenuse  is  (cos q , sin q)  where q is the angle between the x axis and the hypotenuse.   As the hypotenuse = 1 the opposite and adjacent sides of the triangle < 1   so sin and cos of q  must both be  <= 1.
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Answer:

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Step-by-step explanation:

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7 0
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S_A_V [24]

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8 0
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Gemiola [76]

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4 0
3 years ago
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Nataly [62]
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6 0
2 years ago
Which values are solutions to the inequality –3x – 4 &lt; 2? Check all of the boxes that apply.
luda_lava [24]

Answer:

x>-2

Step-by-step explanation:

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–3x – 4 < 2

Before starting we need to understand 1 rule of inequalities. That is:

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< changes to >

and

≥  change  to ≤

and vice versa...

Now, let's go ahead and solve the inequality:

-3x-4

"x" is the set of all values that is greater than "-2". So that's the answer.

x > -2

4 0
3 years ago
Read 2 more answers
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