Given that
3 cos 80° cosec 10° + 2 sin 59° sec 31°
⇛3 cos(90°-10°) cosec 10°+2 sin (90°-31°) sec 31°
We know that
sin (90° - A) = cos A
cos (90°-A) = sin A
⇛3 sin 10° cosec 10° + 2 cos 31° sec 31°
⇛3 sin 10° (1/sin 10°) + 2 cos 31° (1/cos 31°)
⇛3 (sin 10°/sin 10°) + 2 (cos 31°/cos 31°)
⇛3 (1) + 2(1)
⇛3+2
⇛5
<u>Answer</u><u>:</u> Therefore, 3cos 80°cosec 10°+2cos 59°sec 31° = 5.
<u>also</u><u> read</u><u> similar</u><u> questions</u><u>:</u> (sin teta + sec teta)^ + (cos teta+ cosec teta )^ = (1 + sec x cosec)^
brainly.com/question/87846?referrer
Answer: You will need 3.5lbs of the cheaper candy
and 5 lbs of the expensive candy.
Step-by-step explanation:
Let x represent the number of pounds of the cheaper candy that you would need.
Let y represent the number of pounds of the expensive candy that you would need.
You would like to have 8.5 lbs of a candy mixture. It means that
x + y = 8.5
You have one type of candy that sells for $1.70/lb and another type of candy that sells for $3.40/lb. The candy mixture would sell for $2.70/lb. It means that the total cost of the mixture would be 8.5 × 2.7 = $22.95. The expression would be
1.7x + 3.4y = 22.95- - - - - - - - - - - 1
Substituting x = 8.5 - y into equation 1, it becomes
1.7(8.5 - y) + 3.4y = 22.95
14.45 - 1.7y + 3.4y = 22.95
- 1.7y + 3.4y = 22.95 - 14.45
1.7y = 8.5
y = 8.5/1.7
y = 5
x = 8.5 - y = 8.5 - 5
x = 3.5
Answer:
Day 13
Step-by-step explanation:
If you add on both side 13 time you get 90
