3 years ago

PLEASE HELP ME!!!!!

1 answer:

6 0

The answer is c eight units

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stealth61 [152]

Answer:

4/5

Step-by-step explanation:

4 0

3 years ago

Novosadov [1.4K]

Is there a graph maybe post a picture??

6 0

3 years ago

Volgvan

This is very similar to the last question:-

0.51No = No e^_0.0001t

t = ln 0.51 / 0.0001

= 6733 years

6 0

3 years ago

ASHA 777 [7]

F(x)=6x^4-10x^3+40x-50, plug 2 in for x
f(2)=6(2)^4-10(3)^3+40(2)-50
f(2)=12^4-30^3+80-50
f(2)=20735-27,000+80-50
f(2)=-6,235

4 0

3 years ago

Serjik [45]

Answer: 0.27648

Step-by-step explanation:

Given : The proportion of all individuals have group A blood : p=0.040

Total individuals give blood : n= 6

Let X be the number of individuals have group A blood.

Since all individual are independent of each other.

$X\sim Bin(n=6, p=0.40)$

Formula : $P(X=x)=^nC_xp^x(1-p)^{n-x}$ , where n= sample size , p = probability of getting success in each trial.

The probability that exactly three of the individuals have group A blood. :

$P(x=3)= ^6C_3(0.40)^3(1-0.4)^3\\\\= \dfrac{6!}{3!3!}\times(0.40)^3(0.60)^3\\\\=0.27648$

The probability that exactly three of the individuals have group A blood. is 0.27648

8 0

3 years ago