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IgorC [24]
3 years ago
12

Traffic shaping reduces traffic by ________. preventing certain undesirable traffic from entering the network limiting the amoun

t of certain undesirable traffic entering the network both preventing certain undesirable traffic from entering the network and limiting the amount of certain undesirable traffic entering the network neither preventing certain undesirable traffic from entering the network nor limiting the amount of certain undesirable traffic entering the network
Computers and Technology
1 answer:
Lera25 [3.4K]3 years ago
5 0

Answer:

Explanation:

Traffic Shaping is a technique for managing congestion on a network by delaying the flow of less important/desired packets on the network so more valuable/desirables ones are able to pass. Traffic shaping reduces traffic by preventing certain undesirable traffic from entering the network as well as limiting the amount of certain undesirable traffic entering the network.

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3 years ago
Candy Kane Cosmetics (CKC) produces Leslie Perfume, which requires chemicals and labor. Two production processes are available:
Vilka [71]

Answer:

  1. Divide the resources into three parts using the corresponding process 1, process 1, and process 2 formats to maximize the use of the resources.
  2. Get the expected revenue by calculating the product of the total perfume in ounce and the price of an ounce of perfume.
  3. Increase the advertisement hours of the product.
  4. subtract the advert fee from the generated revenue to get the actual revenue.
  5. subtract the cost of production from the actual revenue to get the actual profit.

Explanation:

The get maximum profit, all the resources must be exhausted in production. The labor is divided into a ratio of 1:1:2 ( which is 5000, 5000, 1000), while the chemical units are in the ratio of 2:2:3 (10000,10000,15000). This would produce in each individual processes; 15000, 15000 and 25000 oz, which is a total of 55000 oz of perfume.

The expected revenue is $275000. If 1000oz from the 55000oz of perfume is sold without advertisement, model Jenny's awareness of the perfume increases the demand by 200oz per hour, therefore, 24hours would field 4800oz demanded, which would only take 270 hours to distribute all remaining perfumes.

The cost of production would be $130000 for labor and chemical resources plus the advert cost of $27000 ( 270 hours by 100) which is a total cost of $157000. The actual profit is $118000 ( $275000 - $157000).

3 0
3 years ago
In this lab, you use the flowchart and pseudocode found in the figures below to add code to a partially created C++ program. Whe
never [62]

Answer:

The equivalent program in C++:

#include<iostream>

#include <sstream>

using namespace std;

int main(){

   string Score, Rank;

   cout<<"Enter student score and class rank: ";

   cin>>Score>>Rank;

   int testScore = 0, classRank = 0;

   stringstream sstream(Score);

   sstream>>testScore;

   

   stringstream tream(Rank);

   tream>>classRank;

   

   if (testScore >= 90){

       if(classRank >=25){cout<<"Accept";}

       else{cout<<"Reject";}

   }

   else if(testScore >= 80){

       if(classRank >=50){cout<<"Accept";}

       else{cout<<"Reject";}

   }

   else if(testScore >= 70){

       if(classRank >=75){cout<<"Accept";}

       else{cout<<"Reject";}

   }

   else{cout<<"Reject";}

   return 0;

}

Explanation:

This declares Score and Rank as string variables

   string Score, Rank;

This prompts the user for score and class rank

   cout<<"Enter student score and class rank: ";

This gets the user input

   cin>>Score>>Rank;

This declarees testScore and classRank as integer; and also initializes them to 0

   int testScore = 0, classRank = 0;

The following converts string Score to integer testScore

<em>    stringstream sstream(Score);</em>

<em>    sstream>>testScore;</em>

The following converts string Rank to integer classRank

   stringstream tream(Rank);

   tream>>classRank;

The following conditions implement the conditions as given in the question.    

If testScore >= 90

<em>    if (testScore >= 90){</em>

If classRank >=25

<em>        if(classRank >=25){cout<<"Accept";}</em>

If otherwise

<em>        else{cout<<"Reject";}</em>

<em>    } ---</em>

If testScore >= 80

<em>    else if(testScore >= 80){</em>

If classRank >=50

<em>        if(classRank >=50){cout<<"Accept";}</em>

If otherwise

<em>        else{cout<<"Reject";}</em>

<em>    }</em>

If testScore >= 70

<em>    else if(testScore >= 70){</em>

If classRank >=75

<em>        if(classRank >=75){cout<<"Accept";}</em>

If otherwise

<em>        else{cout<<"Reject";}</em>

<em>    }</em>

For testScore less than 70

<em>    else{cout<<"Reject";}</em>

<em />

3 0
2 years ago
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