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Evgesh-ka [11]
3 years ago
12

Thanks for the help it is very much appreciated

Mathematics
1 answer:
Ne4ueva [31]3 years ago
6 0

<5 + <3 = 180    true

<8 + <2 =180   true

<4 + <6 = 180  true

<10 + <8 = 180 false

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Solve the inequality, -4 less than 4(6y-12)-2y
erastova [34]

-4 < 4(6y - 12) - 2y

<em><u>Distributive property.</u></em>

-4 < 24y - 48 - 2y

<em><u>Combine like terms.</u></em>

-4 < 22y - 48

<em><u>Add 48 to both sides.</u></em>

44 < 22y

<em><u>Divide both sides by 22.</u></em>

2 < y

The value of y is greater than the value of 2.

5 0
3 years ago
N × $3.05 = $305.00=
sdas [7]

Answer:

n = 100

Step-by-step explanation:

Step 1:

n × $3.05 = $305            Equation

Step 2:

n = $305 ÷ $3.05          Divide

Answer:

n = 100

Hope This Helps :)

4 0
3 years ago
2. Order the numbers from least to greatest.
kari74 [83]

Answer:

-5, -2, -1, 0, 7

the answer is D

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
I need help. ASAP!<br> Divide.<br><br><br> (3b^3 – 10b^2 + 4) ÷ (3b – 1)
viktelen [127]

Step-by-step explanation:

try surfing how to divide a function by the long division method

3 0
3 years ago
Give me a correct answer, My answer probably wrong.
Georgia [21]

Hello!

This is a problem about the general solution of a differential equation.

What we can first do here is separate the variables so that we have the same variable for each side (ex. dy with the y term and dx with the x term).

\frac{dy}{dx}=\frac{x-1}{3y^2}

3y^2dy=x-1dx

Then, we can integrate using the power rule to get rid of the differentiating terms, remember to add the constant of integration, C, to at least one side of the resulting equation.

y^3=\frac{1}{2}x^2-x+C

Then here, we just solve for y and we have our general solution.

y=\sqrt[3]{\frac{1}{2}x^2-x+C}

We can see that answer choice D has an equivalent equation, so answer choice D is the correct answer.

Hope this helps!

3 0
2 years ago
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