Answer:
(a): The normal force on the car from the track when the car's speed is v= 7.6 m/s is FN= -6696 N.
(b): The normal force on the car from the track when the car's speed is v= 17 m/s is FN= 8912.7 N.
Explanation:
m= 1080 kg
r= 16m
v1= 7.6 m/s
v2= 17 m/s
g= 9.81 m/s²
v1= w1*r
w1= v1/r
w1= 0.475 rad/s
ac1= w1² * r
ac1= 3.61 m/s²
FN= m * (ac1 - g)
FN= -6696 N (a)
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v2= w2*r
w2= v2/r
w2= 1.06 rad/s
ac2= w2² * r
ac2= 18.06 m/s²
FN= m * (ac2 - g)
FN= 8912.7 N (b)
Answer:
Weight on Venus = 443.75 N
Explanation:
Weight of a body is the product of mass and acceleration due to gravity.
So we have
Weight = Mass x Acceleration due to gravity
W = mg
Mass, m = 50 kg
Acceleration due to gravity, g = 8.875 m/s²
W = 50 x 8.875 = 443.75 N
Weight on Venus = 443.75 N
Answer:
Weight
a) weight's vertical component = Normal upward force
b) weight's horizontal component = Friction force = (mass of ball)(acceleration)
These forces depend upon the track,
1) inclined or horizontal
2) steepness.
Explanation
The force of gravity points straight down, but a ball rolling down a ramp doesn't go straight down, it follows the ramp. Therefore, only the component of the weight which points along the direction of the ball's motion can accelerate the ball.
weight's horizontal component = Friction force = (mass of ball)(acceleration)
The other component pushes the ball into the ramp, and the ramp pushes back.
If the ramp is horizontal, then the ball does not accelerate, as gravity pushes the ball into the ramp and not along the surface of the ramp. Hope this helps. Can u give me brainliest
Explanation:
<h2>Answer</h2>
1 V = 1 kg m2 s−² C
1 V = 1 kg m2 s−³ A−1
(one kilogram meter squared per second cubed per ampere)
<h2>Explanation</h2>
<em>The work required to move an electric charge of one coulomb through an electrical potential difference of one volt,</em>
<h2> Volts = Joules / Coulombs</h2><h2 />
Joules = Newton x metre
Volts = Nm / coulombs
Newton = kg x metre / second ²
Volts = kg x metre / second ² coulombs
Volt in terms of meters (m), seconds (s), kilograms (kg), and coulombs (c)
<h3>For further:</h3>
Coulomb = Amp * second
Volts = kg x metre / second ³ Amp
<h2 />
It is not possible to explain the interaction of the rod and pieces of paper as a gravitational interaction.
<h3>What is Gravitational interaction?</h3>
This is defined as the interaction between a particle or body resulting from their mass. This type of interaction is usually weak and occurs in all distances possible.
It is not gravitational interaction, because the rod attracts paper only against the gravitational force of the earth and there is no attraction between both bodies under a different condition.
This is therefore the reason why it is not possible to explain the interaction of the rod and pieces of paper as a gravitational interaction.
Read more about Gravitational interaction here brainly.com/question/25624188
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