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solmaris [256]
3 years ago
11

Upon what basic quantity does kinetic energy depend?

Physics
1 answer:
natta225 [31]3 years ago
6 0
The velocity of the object. because the greater the movement in particles the greater would be the kinetic energy. 
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A nucleus with a mass number of 64 has a mean radius of about: _________.
dangina [55]

Answer:

The correct option is A

Explanation:

From the question we are told that

The mass number is A= 64

Generally the mean radius is mathematically evaluated as

R  =  R_o A^{\frac{1}{3} }

Here R_o is a constant with a value  R_o =1.2*10^{-15}

So  

     R  =  1.2*10^{-15} *  64^{\frac{1}{3} }

      R  =   4.8 *10^{-15}

        R  =   4.8\ fm

5 0
3 years ago
List three (3) specific examples of each biological<br> Homeostasis:<br> Metabolism:<br> Growth:
Andre45 [30]

Answer:

Homeostasis: When bacteria or viruses that can make you ill get into your body, your lymphatic system kicks in to help maintain homeostasis.

Metabolism: The processes of making and breaking down glucose molecules are example of metabolism.(respiration and photosynthesis)

Growth:The liver continues to form new cells to replace senescent and dying ones.

Hope these examples help you.

4 0
3 years ago
A 2.00 kg block on a horizontal floor is attached to a horizontal spring that is initially compressed 0.0300 m . The spring has
iogann1982 [59]

Answer:

v = 0.41 m/s

Explanation:

  • In this case, the change in the mechanical energy, is equal to the work done by the fricition force on the block.
  • At any point, the total mechanical energy is the sum of the kinetic energy plus the elastic potential energy.
  • So, we can write the following general equation, taking the initial and final values of the energies:

       \Delta K + \Delta U = W_{ffr}  (1)

  • Since the block and spring start at rest, the change in the kinetic energy is just the final kinetic energy value, Kf.
  • ⇒ Kf = 1/2*m*vf²  (2)
  • The change in the potential energy, can be written as follows:

       \Delta U = U_{f}  - U_{o}  = \frac{1}{2} * k * (x_{f} ^{2} - x_{0} ^{2} ) (3)

       where k = force constant = 815 N/m

       xf = final displacement of the block = 0.01 m (taking as x=0 the position

      for the spring at equilibrium)

      x₀ = initial displacement of  the block = 0.03 m

  • Regarding the work done by the force of friction, it can be written as follows:

       W_{ffr} = - \mu_{k}* F_{n} * \Delta x  (4)

       where μk = coefficient of kinettic friction, Fn = normal force, and Δx =

       horizontal displacement.

  • Since the surface is horizontal, and no acceleration is present in the vertical direction, the normal force must be equal and opposite to the force due to gravity, Fg:
  • Fn = Fg= m*g (5)
  • Replacing (5) in (4), and (3) and (4) in (1), and rearranging, we get:

        \frac{1}{2} * m* v^{2} = W_{ffr} - \Delta U = W_{ffr} - (U_{f} -U_{o})  (6)

        \frac{1}{2} * m* v^{2} = (- \mu_{k}* m*g* \Delta x)  -\frac{1}{2} * k * (x_{f} ^{2} - x_{0} ^{2} ) (7)

  • Replacing by the values of m, k, g, xf and x₀, in (7) and solving for v, we finally get:

    \frac{1}{2} * 2.00 kg* v^{2}  = (-0.4*2.00 kg*9.8m/s2*0.02m) +( (\frac{1}{2} *815 N/m)* (0.03m)^{2} - (0.01m)^{2}) = -0.1568 J + 0.326 J (8)

  • v =\sqrt{(0.326-0.1568}  =  0.41 m/s  (9)
7 0
3 years ago
A uniform solid cylinder with a radius of 10 cm and a mass of 3.0 kg is rotating about its center with an angular speed of 33.4
DENIUS [597]

Answer:

Is the equation for Ec=1/2 m(Dv)^2 where Dv is the difference between the angular speed & the areolar speed?

5 0
3 years ago
The electron has the positron as its antiparticle.<br><br> A True<br> B False
Sphinxa [80]
The answer would be true
8 0
3 years ago
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