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AysviL [449]
3 years ago
7

Consider the following chemical equilibrium: CaCO3 (s) Cao (s)+cO2 (g) Now write an equation below that shows how to calculate K

c from Kp for this reaction at an absolute temperature T. You can assume T is comfortably above room temperature. If you include any common physical constants in your equation be sure you use their standard symbols, found in the ALEKS Calculator.
Chemistry
1 answer:
True [87]3 years ago
4 0

Answer:

Kc = Kp/(RT)

Explanation:

Let's consider the following chemical equilibrium:

CaCO₃(s) ⇄ CaO(s) + CO₂(g)

Given the pressure equilibrium constant Kp = pCO₂

We can calculate the concentration equilibrium constant (Kc) using the following expression.

Kc = Kp/(RT)^{\Delta n(g)}

where,

R is the ideal gas constant

T is the absolute temperature

Δn(g) = moles of gaseous products - moles of gaseous reactants = 1 - 0 = 1

The expression for this reaction is:

Kc = Kp/(RT)

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Answer:

0.287 mole of PCl5.

Explanation:

We'll begin by calculating the number of mole in 51g of Cl2. This is illustrated below:

Molar mass of Cl2 = 2 x 35.5 = 71g/mol

Mass of Cl2 = 51g

Number of mole of Cl2 =..?

Mole = Mass /Molar Mass

Number of mole of Cl2 = 51/71 = 0.718 mole

Next, we shall write the balanced equation for the reaction. This is given below:

P4 + 10Cl2 → 4PCl5

Finally, we determine the number of mole of PCl5 produced from the reaction as follow:

From the balanced equation above,

10 moles of Cl2 reacted to produce 4 moles of PCl5.

Therefore, 0.718 mole of Cl2 will react to produce = (0.718 x 4)/10 = 0.287 mole of PCl5.

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3 years ago
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Answer: False

Explanation:

Depending on the situation it can be shorter or longer than 10 days

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4 years ago
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What is the possible or stored energy in an object called?
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Answer:

Potential energy is the energy stored within an object, due to the object's position, arrangement or state. Potential energy is one of the two main forms of energy, along with kinetic energy.

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If I have 0.725 moles of gas at a temperature of 105 K and a pressure of 3.75 atmospheres the volume of the gas 1.66 litres.

Explanation:

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rearranging the equation to calculate volume:

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putting the values in the equation:

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