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ludmilkaskok [199]
3 years ago
9

A kinetics experiment is set up to collect the gas that is generated when a sample of chalk, consisting primarily of solid CaCO3

, is added to a solution of ethanoic acid, CH COOH. The rate of reaction between CaCo, and CH3COOH is determined by measuring the volume of gas generated at 25°C and I atm as a function of time. Which of the following experimental conditions is most likely to increase the rate of gas production?
(A) Decreasing the volume of ethanoic acid solution used in the experiment acid solution used in the experiment experiment is performed
(B) Decreasing the concentration of the ethanoic
(C) Decreasing the temperature at which the
(D) Decreasing the particle size of the CacO, by grinding it into a fine powder
Chemistry
1 answer:
velikii [3]3 years ago
8 0

(D) Decreasing the particle size of the CacO, by grinding it into a fine powder

Explanation:

To produce more gases by increasing the rate of the chemical reaction, if we grind the chalk into powder, this should walk.

The rate at which chemical reactions takes place is a measure of the speed of  the reaction.

Some factors control the rate of chemical reactions. They are:

  1. Nature of reactants
  2. Concentration of reactants or pressure if gaseous.
  3. Temperature
  4. Presence of a catalyst
  5. Sunlight

The most applicable in this scenario is grinding the chalk into fine powder. This process increases the surface area exposed. Surface area exposed proportionally affects the rate of a reaction.

Learn more:

Surface area brainly.com/question/9666705

#learnwithBrainly

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The N2O4−NO2 reversible reaction is found to have the following equilibrium partial pressures at 100∘C. Calculate Kp for the rea
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4 years ago
Could someone help me with this?
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Solving part-1 only

#1

KMnO_4

  • Transition metal is Manganese (Mn)

#2

Actually it's the oxidation number of Mn

Let's find how?

\\ \tt\Rrightarrow x+1+4(-2)=0

\\ \tt\Rrightarrow x+1-8=0

\\ \tt\Rrightarrow x-7=0

\\ \tt\Rrightarrow x=+7

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#3

  • Purple as per the color of potassium permanganate

#4

\boxed{\begin{array}{c|c|c}\boxed{\bf Tube} &\boxed{\bf Charge} &\boxed{\bf No\:of\; electrons\: loss}\\ \sf 2 &\sf +6 &\sf 6e^-\\ \sf 3& \sf +2 &\sf 2e- \\ \sf 4 &\sf 4 &\sf 4e^-\end{array}}

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