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MAVERICK [17]
3 years ago
12

Which of the following can be true about a chemical reaction

Chemistry
1 answer:
MissTica3 years ago
3 0
chemical reactions can release heat (a)
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Find the appropriate number of significant figures
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Non-zero digits are always significant

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Si hay algo que sucedió entre ustedes raro o un comportamiento que tuviste con esa persona o que te vio hacer asi como le pudieron decir algo de ti que no le gustara a tu amigo hace que se comporte raro contigo

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How does an embryo develop from a fertilized egg?]
faltersainse [42]

Answer: Hope this helps

<h3>Explanation: <u><em>The fertilized egg zygote divides repeatedly as it moves down the fallopian tube to the uterus. First, the zygote becomes a solid ball of cells. ... Inside the uterus, the blastocyst implants in the wall of the uterus, where it develops into an embryo attached to a placenta and surrounded by fluid-filled membranes.</em></u></h3><h3><u><em /></u></h3>
6 0
4 years ago
Purchasing the correctly sized BMX bike is based on the height of the rider. In order to fit a customer, the salesman can use th
Phantasy [73]
Answer: Your best answer is A.

Explanation: 1.35 is a constant and thus is does not change. The equation can be simplified to-
“b = (0.29 x h)+ 1.35”
So, if your rider is say 60 inches tall, the equation would change to-
“b = (0.29 x 60)+ 1.35”
Then to-
“b = (17.4) + 1.35” or “b = 17.4 + 1.35”
And therefore the size of the BMX bike frame in inches would be-
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Hope this helped :)
5 0
2 years ago
Explain how energy is conserved between this reaction and the and surrounding environment C3H8+4O2-&gt;3CO2+4H2O+ heat (-2218.6)
alukav5142 [94]

Answer:

The heat of formation = Heat of formation of the products - Heat of formation of the reactants

= -2323 + 104 = -2219 ≈ -2218.6 kJ/mol.

Explanation:

The law of conservation of energy states that the total energy is constant in any process. Energy may change in form or be transferred from one system to another, but the total remains the same

The heat of formation of C₃H₈ is 3C + 4 H₂ → C₃H₈ \Delta H^{\circ}_f  -104 kJ/mol

The heat of formation of O₂ is O₂ (g) → O₂ (g)  \Delta H^{\circ}_f  0 kJ/mol

The heat of formation of H₂O is H₂(g) + 1/2 O₂→ H₂O (g)  \Delta H^{\circ}_f  -286kJ/mol

The heat of formation of CO₂ is C (s) + O₂ (g) → CO₂ (g)  \Delta H^{\circ}_f  -393 kJ/mol

Therefore, in the given  reaction we have;

C₃H₈ + 4 O₂ → 3 CO₂ + 4 H₂O

The heat of formation = Heat of formation of the products - Heat of formation of the reactants

The heat of formation = 3 × (-393) + 4 × (-286) - (-104) = -2219 ≈ -2218.6 kJ/mol.

5 0
4 years ago
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