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m_a_m_a [10]
3 years ago
8

Alisa, Mykia, and Martin decide to share the responsibility of walking their dog every day. There are 365 days in a year. How ma

ny days each year does Alisa need to walk the dog?
Mathematics
1 answer:
shutvik [7]3 years ago
6 0

Answer: 121 2/3 days

Step-by-step explanation:

Number of days in a year = 365 days

Number of friends = 3 friends

The number of days each year that Alisa need to walk the dog will be:

= Number of days in a year / Number of friends.

= 365 / 3

= 121 2/3 days

= 121 days + (2/3 × 24hours)

= 121 days 16 hours

Note that 24 hours = 1 day

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Find the equation of the line use exact numbers
mart [117]

Answer:

y = -³/2x + 3

Step-by-step explanation:

To find the equation of the line in slope-intercept form, y = mx + b, we need to finder the slope (m) and the y-intercept (b).

✔️Slope (m) = ∆y/∆x

Using two points on the line, (0, 3) and (2, 0),

Slope = (0 - 3)/(2 - 0) = -3/2

Slope (m) = -³/2

✔️y-intercept (b) = 3 (this is the y-cooordinate of the point where the line intercepts the y-axis)

✔️To write the equation, substitute m = -³/2 and b = 3 into y = mx + b

This:

y = -³/2x + 3

4 0
3 years ago
Approximately how much principal would need to be placed into an account earning 3.575% interest compounded
Zepler [3.9K]

Answer: $23,377

Step-by-step explanation:

4 0
3 years ago
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Linda had breakfast in a café. It cost $12.40. She paid with a $20 bill.
Westkost [7]
Around 8$ back. The exact amount would be 7.60$
7 0
3 years ago
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An object oscillates as it moves along the
Sauron [17]

Using it's formula, it is found that the displacement between t= 0  and t = 1 second is of 0 m.

The equation of motion is given by:

x(t) = 4\sin{\left(\pi t + \frac{\pi}{6}\right)}

The <em>displacement </em><u>between t= 0  and t = 1 second</u> is given by:

d = x(1) - x(0)

Hence:

x(1) = 4\sin{\left(\pi + \frac{\pi}{6}\right)} = 4\sin{\left(\frac{7\pi}{6}\right)} = -\frac{4}{2} = -2

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Then:

d = x(1) - x(0) = -2 + 2 = 0

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You can learn more about displacement at brainly.com/question/248054

5 0
3 years ago
TASK 3= 50 POINTSSS
Nadusha1986 [10]
After \: 1 \: year:25400 + 25400 \times 11\% = 25400 + 25400 \times 0.11 = 25400(1 + 0.11) = 25400 \times 1.11 \\ After \: 2 \: year:25400 \times {1.11}^{2} \\ After \: x \: year:25400 \times {1.11}^{x} \\ We\: have\: an\: inequality:25400 \times {1.11}^{x} > 501170 \\ \Leftrightarrow {1.11}^{x} > \frac{50117}{2540}\\ \Leftrightarrow x > \log _{1.11}(\frac{50117}{2540}) \\ \Leftrightarrow x>29\\\Rightarrow After\: 29\: years
4 0
3 years ago
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