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Natasha_Volkova [10]
4 years ago
14

Please Help! LOOK BELOW! The first hexagon is dilated to form the second hexagon.

Mathematics
2 answers:
mote1985 [20]4 years ago
8 0

Answer:

Part 1) Option B. 4

Part 2) Option A. An enlargement

Step-by-step explanation:

we know that

The scale factor is equal to the length side of the dilated figure divided to the length side of the original figure

so

scale\ factor=\frac{0.8}{0.2} =4

The dilation represent an enlargement because the scale factor is greater than 1

4> 1 -------> represent an enlargement

Zolol [24]4 years ago
6 0
The scale factor is B. 4.  To get the second shape, you multiply the sides of the first shape by 4.  
This is an A. enlargement.  To get the second shape, the sides of the first shape must be increased/enlarged.
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Which expression is equivalent to 16+2×36?​
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Answer:

18\cdot36

Step-by-step explanation:

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Find the area for the image below A (0,6) B (5, -4) C(5,2 ) D (9,2) E (9,6)
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3 years ago
Round 0.378 to the place underlined digit 3
mel-nik [20]

Answer:

0.38

Step-by-step explanation:

7 is the 3rd digit, so 8 is greater then 5, so you round up, if it is correct, can you give brainiest

3 0
4 years ago
Read 2 more answers
Please help I don’t really understand how to go about it.
Airida [17]
\bf \textit{sum of an arithmetic sequence}
\\\\
S_n=\cfrac{n(a_1+a_n)}{2}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
----------\\
S_n=795\\
a_1=102\\
a_n=57
\end{cases}
\\\\\\
795=\cfrac{n(102+57)}{2}\implies 1590=159n
\\\\\\
\cfrac{1590}{159}=n\implies 10=n\\\\
-------------------------------

so the nth term is really the 10th term, and we know that's 57, thus

\bf n^{th}\textit{ term of an arithmetic sequence}
\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
n=10\\
a_{10}=57\\
a_1=102
\end{cases}
\\\\\\
57=102+(10-1)d\implies 57=102+9d\implies -45=9d
\\\\\\
\cfrac{-45}{9}=d\implies -5=d

so, that's the common difference... .so you'd surely know what the 3rd term is, notice the first one is 102.
3 0
3 years ago
The san paulo community swimming pool can be filled in 12 hr if water enters through a pipe alone or in 30 hr if water enters th
Nuetrik [128]

Alright, lets gets started.

If water enters through a pipe alone, swimming pool can be filled in 12 hr.

Or say, in 12 hrs, swimming pool can be filled with help of pipe.

It means in 1 hr, the part of swimming pool filled = \frac{1}{12} (For pipe only)

Similarly, with hose only, , in 1 hr, the part of swimming pool filled = \frac{1}{30}

So, water is coming from both, pipe and hose , then in 1 hr, the part of pool filled will be = \frac{1}{12}  + \frac{1}{30}

Suppose in x hrs, with both supplies, pipe and hose, pool is filled.

Means

\frac{1}{12}  + \frac{1}{30}  = \frac{1}{x}

making common denominator

\frac{30}{360}   + \frac{12}{360}  = \frac{1}{x}

\frac{30 + 12}{360} = \frac{1}{x}

\frac{42}{360}  = \frac{1}{x}

Flipping

\frac{360}{42}  = x

x = \frac{60}{7}

Means 8.57 hrs : Answer

Hope it will help :)

7 0
3 years ago
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