Answer:
The answer is 1/3
Step-by-step explanation:
Let the events of getting the no. greater than 4 be (>4). 
Then, 
<em>n</em><em>(</em><em>s</em><em>)</em><em> </em><em>=</em><em> </em><em>6</em>
<em>n</em><em>(</em><em>></em><em>4</em><em>)</em><em> </em><em>=</em><em> </em><em>2</em>
<em>P</em><em>(</em><em>></em><em>4</em><em>)</em><em> </em><em>=</em><em> </em><em>n</em><em>(</em><em>></em><em>4</em><em>)</em><em>/</em><em>n</em><em>(</em><em>s</em><em>)</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>2</em><em>/</em><em>6</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>1</em><em>/</em><em>3</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>
 
        
             
        
        
        
Answer:
Each factory should supply 100 units
x = 100 units
y = 100 units
Step-by-step explanation:
Since the total production must be 200 units, then x + y = 200.
The cost function can be rewritten as a function of 'x' as follows:

The value of 'x' for which the derivate of the cost function is zero, is the production level that minimizes cost:

In order to minimize production costs, each factory should supply 100 units
 
        
             
        
        
        
Answer:
1/2
Step-by-step explanation:
sqrt(16)=4 then 1/4+1/4=2/4=1/2
 
        
                    
             
        
        
        
we get, x = 1 and y = 5 
Step-by-step explanation:
from first equation we get,
y = 4x +1 
then,
putting the value of y in second equation :-
=》3x + 2y = 13
=》3x + 2 (4x + 1) = 13
=》3x + 8x + 2 = 13
=》11x = 13 - 2
=》11x = 11
=》 x = 11 / 11
=》 x = 1
putting the value of x in equation 1 
=》y = 4x + 1
=》y = (4 × 1) + 1 
=》y = 4 + 1 
=》y = 5
 
        
                    
             
        
        
        
Answer:
m∠1= m∠5= 100°, m∠2= m∠6= 80°, m∠4=m∠8= 155°, m∠3= m∠7= 25°
Step-by-step explanation:
Supposing ∠1,∠2  make up a straight angle.Let ∠1, ∠5 and ∠2 and ∠6 be corresponding angles on a transversal  drawn on two  parallel lines. ∠3,∠4 and∠5 ∠6  be interior angles
If m ∠= 80° them m∠ 1= 100°
As ∠1= 4. m∠3 therefore 
100°= 4.m∠3
m∠3= 100/4= 25°
Again supposing m∠3+ m∠4= 180°
m∠4= 180°- 25°= 155°
m∠4 =m∠8= 155°
m∠8 + m∠7= 180°
m∠7= 180°- 155°= 25°
Let  ∠5 and ∠1 be corresponding angles so m∠5= m∠1= 100°
and m∠6= m∠2= 80°