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Vika [28.1K]
4 years ago
5

A student is growing two plants for a science experiment. Each plant was a different height at the start of the experiment. Plan

t A was given only water and plant B was given water and food. The system of equations show how the heights of the plants, y, in inches have change over x weeks. Plant A: y = 8 + ½ x Plant B: y = 4 + (5/4) x
Mathematics
1 answer:
k0ka [10]4 years ago
5 0

Answer:

A: 12.5 per week B= 12.75

Step-by-step explanation:

1/2 times 7 (days in a week) is 3.5. So A is 8+3.5=12.5. 7 times 5/4 is 8.75. So B is 4+8.75=12.75

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ILL BRAINLIEST YOU PLEASE HELP ME
gtnhenbr [62]

Answer:

Option C

The length of RT is 14

Step-by-step explanation:

For a given Right Triangle

m∠R = 90°, RG = 17, TG = 22

Now, <u>By Pythagoras Theorem</u>

(RT)² + (RG)² = (TG)²

(RT)² = (TG)² - (RG)²

(RT)² = (22)² - (17)²

(RT)² = 484 - 289

(RT)² = 195

RT = √195

RT = √195 = 13.96 = 14

Thus, The length of RT is 14

<u>-TheUnknownScientist</u>

4 0
3 years ago
A different children's party cost £225.50 How many children were at the party?​
Alecsey [184]
Hi, I think you forgot to write a part of the problem, could you write the rest in the comments please. I would be happy to help you
8 0
3 years ago
Ling lives 2 miles from school. It took him 15 minutes to bike from school to home. The first half of the distance he biked at a
alexdok [17]
A) time = distance/speed
For the first half of the trip, the time used was
.. (1 mi)/(12 mi/h) = (1/12) h = 5 minutes
Then the last half of the trip took 10 minutes, 1/6 hour.
.. speed = distance/time
.. = (1 mi)/(1/6 h) = 6 mi/h

The speed for the last half of the trip was 6 mph.


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8 0
4 years ago
The graph of a system of equations with the same slope and the same y-intercepts will have no solutions.
Rasek [7]
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4 0
4 years ago
Read 2 more answers
The steps to derive the quadratic formula are shown below:
Georgia [21]

Answer: x+\frac{b}{2a}=\pm \frac{\sqrt{b^2 - 4ac}}{\sqrt{4a^2}}

Step-by-step explanation:

We can rewrite the left hand side as a perfect square, more specifically

\left(x+\frac{b}{2a} \right)^2

So, taking the square root of both sides,

x+\frac{b}{2a}=\pm \frac{\sqrt{b^2 - 4ac}}{\sqrt{4a^2}}

3 0
2 years ago
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