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levacccp [35]
2 years ago
7

9

Mathematics
1 answer:
timofeeve [1]2 years ago
6 0

Answer:the answer is B

Step-by-step explanation:

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AD ??????? so confused what the
Andre45 [30]

Answer:

3.6 cm

Step-by-step explanation:

<u>Triangle Proportionality Theorem</u>

BD : DE = BA : AC

⇒ 6 : 10 = BA : 16

⇒ \mathsf{\dfrac{6}{10} = \dfrac{BA}{16}}

⇒ \mathsf{BA=\dfrac{6}{10} \times16}

⇒ BA = 9.6

AD = BA - BD

⇒ AD = 9.6 - 6 = 3.6 cm

4 0
2 years ago
PLS HELP I NEED THIS IN 2 HOURS PLS DO NOT GIVE ME A LINK FOR AN ANSWER
dybincka [34]

Answer:

The  formula for the area of a parallelogram is base x height.

base x height = area

So, I will form an equation.  b (base)  x 3 ft (height) = 18 1/3

Next divide 3 from 18 1/3, so 18 1/3 divided by 3. This equals1 6 1/9

To check: 6 1/9 x 3 = 18.3333333333 or 18 1/3

Step-by-step explanation:

5 0
3 years ago
Divide.<br><br> 3 1/2 / 4<br> Write your answer in the simplest form
Gennadij [26K]

Answer:

9

Step-by-step explanation:

3 1/2/4=3 1/2*4=3  2=9

5 0
3 years ago
Jada’s teacher ask her to write a three-digit number that uses the digit 4 once and the digit 7 twice. The value of one 7 needs
viva [34]
477

The value of the first 7 from the left is 70.

If you divide 70 by 10, you get the value of the second seven, 7.

Another way to know this is equivalent fractions:

1/10 = 7/10

10 X 7 = 70
1 X 7 = 7
6 0
3 years ago
A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-­‐
cricket20 [7]

Answer:

<u>The final curse load of the local gym instructor is this:</u>

<u>High-­‐impact aerobics = 1</u>

<u>Low-­‐impact aerobics =  4</u>

<u>Jazzercise = 1</u>

<u>Step exercise = 2</u>

Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-­‐impact aerobics, 64 wanted low-­‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-­‐impact aerobics = 8/14.25 = 0.5614

Low-­‐impact aerobics = 64/14.25 = 4.49

Jazzercise = 11/14.25 = 0.7719

Step exercise = 31/14.25 = 2.1754

Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-­‐impact aerobics = 0

Low-­‐impact aerobics =  4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-­‐impact aerobics with .5614.

<u>The final course load is this:</u>

<u>High-­‐impact aerobics = 1</u>

<u>Low-­‐impact aerobics =  4</u>

<u>Jazzercise = 1</u>

<u>Step exercise = 2</u>

7 0
3 years ago
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