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3 years ago

Convert 1,265,341 mm to m.

Physics

2 answers:

kvasek [131]3 years ago

8 0

It’s easy the answer is 1265.341 I think so because It was online :)

Thepotemich [5.8K]3 years ago

7 0

The answer in Meters is going to to 1265.341

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All digits shown on measuring device, plus one estimated digit, are considered_______.

vichka [17]

Significant

Explanation:

All the digits shown on a measuring device and one estimated digit are all considered to be significant.

A significant digit is a set of values that shows how precise a measurement is reported.

Measuring devices such as calculators gives their values in significant digits.

Non- zero digits in a measurement are always significant.
Zero's before a decimal are not significant. Those after a number in a decimal are significant.
Zero's between digits are significant.

learn more:

Significant digits brainly.com/question/2743055

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3 years ago

The world energy consumption was about 6*10^22 J. How much area must a parallel plate capacitor need to store this energy Assume

Nastasia [14]

Answer:

$A = 5 \times 10^{32} m^2$

Explanation:

As we know that the energy stored in the capacitor is given as

$Q = \frac{1}{2}CV^2$

here we know that

$Q = 6 \times 10^{22} J$

also we know that

$V = 5 Volts$

now we have

$6 \times 10^{22} = \frac{1}{2}C(5^2)$

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now we know the formula of capacitance

$C = \frac{\epsilon_0 A}{d}$

$4.8 \times 10^{21} = \frac{(8.85 \times 10^{-12})(A)}{1}$

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3 years ago

Where is each subatomic particle is found in an atom

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Protons and neutrons are located in the nucleus, a dense central core in the middle of the atom, while the electrons are located outside the nucleus.

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3 years ago

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Answer:

a) $v = 6.25\times 10^{5} m/s$

b) $v = 1.73\times 10^{4} m/s$

Explanation:

Given data:

Electric field = 1.47 N/C

velocity of electron is $4.55\times 10^5 m/s$

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$a =\frac{q E}{m}$

$a = \frac{1.6\times 10^{-19} \times 1.47}{9.1\times 10^{-31}}$

$a = 2.58\times 10^{11} m/s^2$

from equation of motion we have

$v^2 = u^2 + 2aS$

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$a = \frac{1.6\times 10^{-19} \times -1.47}{1.6\times 10^{-27}}$

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