Whats an astral projection

Physics

2 answers:

Dominik [7]3 years ago

5 0

Answer:Esotericism

Explanation:

it’s something that’s in intentional out of body experience

uranmaximum [27]3 years ago

5 0

Answer:

Astral projection is a term used in esotericism to describe an intentional out-of-body experience that assumes the existence of a soul or consciousness called an "astral body" that is separate from the physical body and capable of travelling outside it throughout the universe.

Explanation:

You might be interested in

An apple falls because of the gravitational attraction to earth. how does the gravitational attraction of earth to the apple com

Sphinxa [80]

The forces between the apple and Earth are the same in magnitude. Force is the same either way, but the corresponding accelerations of each are different.

8 0

2 years ago

An object of 4 cm length is placed at a distance of 18 cm in front of a convex mirror of radius of curvature 30 cm. Find the pos

erica [24]

Answer:

The position is 8.18cm from the mirror.

Nature is b=virtual

Size is 1.82cm

Explanation:

Note that for a convex mirror, the image distance and the focal length are negative;

Given

Object height H0 = 4cm

object distance u = 18cm

Radius of curvature R = 30cm

Since f = R/2

f = 30/2

f = -15cm

Recall that:

$\frac{1}{f} =\frac{1}{u}+ \frac{1}{v}\\\frac{1}{-15}=\frac{1}{18}+\frac{1}{v} \\\frac{1}{v} =\frac{1}{-15} -\frac{1}{18}\\ \frac{1}{v} = \frac{-18-15}{270}\\\frac{1}{v} = \frac{-33}{270}\\v=\frac{-270}{33}\\v=-8.18cm$

Since the image distance is negative, this shows that the image is a virtual image.

To get the size:

$\frac{H_1}{H_0}=\frac{v}{u}\\\frac{H_1}{4}=\frac{8.18}{18}\\18H_i=32.72\\H_i=\frac{32.72}{18}\\H_i= 1.82cm$

3 0

2 years ago

A 12,000-N car is raised using a hydraulic lift, which consists of a U-tube with arms of unequal areas, filled with incompressib

Natasha_Volkova [10]

Answer:

F = 1958.4 N

Explanation:

By volume conservation of the fluid on both sides we can say that volume of fluid displaced on the side of the car must be equal to the volume of fluid on the other side

so we have

$L_1A_1 = L_2A_2$