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Naily [24]
3 years ago
7

Answered Which of the following values are solutions to the inequality -9>-4+5x

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
3 0

Answer:

-1>x

Step-by-step explanation:

You might be interested in
I have the equations 8x + 3y = 20.50 and 4x + 5y = 22.50<br> How do I solve for x and y?
snow_tiger [21]
8x + 3y = 20.50
-
4x+5y=22.50
=
4x-2y=-2, so you have to divide each number by 2, then
2x-y=-1, so

-y=-1-2x /-1, y=1+2x, then replace it with one original equation like the first one for instance:
8x+3(1+2x)=20.50, then
8x+3+6x=20.50, then
14x=20.50-3
14x=17.5
x=1.25, then solve y:\
y=1+2*(1.25)
y=1+2.5
y=3.5,
So answer is x=1.25, and y=3.5

6 0
3 years ago
Guthrie made the input-output table shown below.
Inga [223]

9514 1404 393

Answer:

  C  3x +1 = y

Step-by-step explanation:

x-values increase by 1 from row to row.

y-values increase by 3 from row to row.

The slope of the linear function is the ratio of the y-increase to the x-increase:

  m = ∆y/∆x = 3/1 = 3

The only offered choice with an x-coefficient of 3 is ...

  C  3x +1 = y

__

If you check this against the table entries, you find it fits.

  3(1) +1 = 4

  3(2) +1 = 7

and so on.

3 0
3 years ago
Use synthetic division to find P (-10) for P(x)=2x^3+14x^2-58x
Savatey [412]
The polynomial remainder theorem states that the remainder upon dividing a polynomial p(x) by x-c is the same as the value of p(c), so to find p(-10) you need to find the remainder upon dividing

\dfrac{2x^3+14x^2-58x}{x+10}

You have

..... | 2 ...  14  ... -58
-10 |    ... -20  ... 60
--------------------------
..... | 2 ...  -6  ....  2

So the quotient and remainder upon dividing is

\dfrac{2x^3+14x^2-58x}{x+10}=2x-6+\dfrac2{x+10}

with a remainder of 2, which means p(-10)=2.
5 0
3 years ago
-3-2(2x-3) simplified
ddd [48]
First Distribute, then subtract and you’ll get -4x+3
6 0
2 years ago
I need help on this parallelograms question.
yarga [219]
180-132+x-6x+12=0
48+x-6x+12=0
48-5x+12=0
60-5x=0
-5x=-60
x=12
3 0
2 years ago
Read 2 more answers
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