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Tanya [424]
3 years ago
10

3 + 12 + 48 + 192 + ... Whats the answer

Mathematics
2 answers:
Alex3 years ago
8 0
The sequence is to take the previous number and multiply by 4, so the sequence is

3 12 48 192 768 3072 12288

add them all up and you get 16383
iren [92.7K]3 years ago
5 0

Answer:

3, 12, 48, 192, 768, 3072, 12288 these are the next seven numbers

Add them all up and you get

<h2>= 16383 Answer C</h2>

Step-by-step explanation:

3, 12, 48, 192

So from 3 to 12 is multiply by 4

So we have checked that it works for all of them

Rule:

Each term is: Two to the power of the number3/4 times the number squared plus 0 times the number

I hope this has helped :)

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3540/6 = 590

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3 years ago
An initial amount of money is placed in an account at an interest rate of 3% per year, compounded continuously. After six years,
insens350 [35]

Hi

Let's call X  the amount in the beginning.  

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6 0
3 years ago
State the property.<br> power property of exponents.
d1i1m1o1n [39]

Answer:

The Power of a Power Property states that if an exponent is being raised to another exponent, you can multiply the exponents. You can use this property to solve a problem like (3x2)3.

Step-by-step explanation:   The Power of a Power Property states that if an exponent is being raised to another exponent, you can multiply the exponents. You can use this property to solve a problem like (3x2)3.

4 0
3 years ago
Please Help 6th Grade Math! Box Plots! 2 questions (Image attached)​
tangare [24]

Answer:

First answer is 14

Second answer is 25

Step-by-step explanation:

Median is the middle ( 1 2 3 4 5 the median would be 3)

You start at 2 and end at 27

List all the numbers from 2 to 27 and come from both ends until you get to the middle number(s)

In this case there are two 14 & 15

14+15=29 29÷2=14.5

Since there are no decimal answers you are left with 14

Range you take the two end numbers and subtract them (27 & 2)

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Hopefully this helps!

4 0
3 years ago
Find the remainder when 1!+2!+3!+...+15! is divided by 15
Anettt [7]

Answer:

  • 3

Step-by-step explanation:

<u>We know that </u>

  • n! = 1*2*3*...*n

<u>We also know that </u>

  • 15 = 3*5

<u>Since 5! = 1*2*3*4*5 is divisible by 15:</u>

  • any n! with n ≥ 5 is divisible by 15.

We need to find the remainder when 1! + 2! + 3! + 4! is divided by 15 as all the rest are divisible by 15.

<u>The sum is:</u>

  • 1! + 2! + 3! + 4! = 1 + 2 + 6 + 24 = 33

<u>The remainder is:</u>

  • 33/15 = 2 rem 3

As we see the remainder is 3

5 0
3 years ago
Read 2 more answers
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