Answer:
- time = 1second
- maximum height = 16m
Step-by-step explanation:
Given the height of a pumpkin t seconds after it is launched from a catapult modelled by the equation
f(t)=-16t²+32t... (1)
The pumpkin reaches its maximum height when the velocity is zero.
Velocity = {d(f(x)}/dt = -32t+32
Since v = 0m/s (at maximum height)
-32t+32 = 0
-32t = -32
t = -32/-32
t = 1sec
The pumpkin reaches its maximum height after 1second.
Maximum height of the pumpkin is gotten by substituting t = 1sec into equation (1)
f(1) = -16(1)²+32(1)
f(1) = -16+32
f(1) = 16m
The maximum height of the pumpkin is 16m
10 more times
On Monday the rover needed to charge 22 times and on Tuesday 12 times.
So the answer is 22-12=10
x= length, y=width
Both the length and width were increased by 60% so now they are:
1.6x and 1.6y
Then they were both reduced by 25% so now they are 75%(100-25) of their previous size so they are:
0.75(1.6x) and 0.75(1.6y)
Their area would be length * width so it would be:
0.75(1.6x) * 0.75(1.6y)
Simplified this would be:
1.2x * 1.2y
Simplified more it would be :
1.44xy which is also 144% of xy which is a 44% increase of the original area (xy)
So the answer is:
44%
The equation would be 0.05x + 3.15 = 5.10
0.05x = 1.95 (subtraction)
x = 39 (division)
39 minutes
