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pogonyaev
3 years ago
5

Rocks are grouped according to

Chemistry
1 answer:
MissTica3 years ago
8 0
<h2>Rocks are grouped according to their formation into three major groups – igneous, sedimentary, and metamorphic rocks </h2>

Explanation:

  • Based on their formation, rocks are further sub-grouped as:
  1. Igneous - Intrusive or extrusive
  2. Sedimentary – Clastic, chemical, or biologic rocks
  3. Metamorphic - Foliated and non-foliated
  • Rocks are also grouped based on their properties like size, shape, texture, chemical composition, permeability, mineralogy, etc.
  • Based on properties rocks are sub-grouped as:
  1. Igneous rocks – coarse or fine-grained; glassy or obsidian; felsic or mafic.
  2. Sedimentary rocks - conglomerate, sandstone, breccia, shale, siltstone, chalk, crystalline or fossiliferous limestone, gypsum, rock salt etc.
  3. Metamorphic rocks - Gneiss, hornfels, mylonites, cataclasties, marble, etc.
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2. D
A radioactive half life refers to the amount of time it will take for half of an original radioactive isotope to decay. 
In the question given above, the half life of the element is 1000. Thus, in 1000 years only half of the original amount will remain. In another 1000 years only 1/4 of the original amount will remain and in another 1000 years only 1/8 of the original amount will remain. Therefore, it will take 3 half lives before 1/8 of the original sample remain.<span />
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3 years ago
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P1V1 = P2V2

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Use these to solve for V2:
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2 years ago
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The rate of a chemical reaction may be defined as Select one: a. the time it takes for the reaction to be completed b. the chang
kaheart [24]
It is A. This is because the rate of reaction is defined as the speed at which the reactants are converted into the products.
8 0
2 years ago
. Consider the following half-reactions:
Vedmedyk [2.9K]

d. Fe(s) and Al(s)

<h3>Further explanation</h3>

In the redox reaction, it is also known  

Reducing agents are substances that experience oxidation  

Oxidizing agents are substances that experience reduction

The metal activity series is expressed in voltaic series  

<em>Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au  </em>

The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent  

The more to the right, the metal is less reactive (harder to release electrons) and the stronger oxidizing agent

So that the metal located on the left can push the metal on the right in the redox reaction  

The electrodes which are easier to reduce than hydrogen (H), have E cells = +

The electrodes which are easier to oxidize than hydrogen have a sign E cell = -

So the above metals or metal ions will reduce Pb²⁺ (aq) will be located to the left of the Pb in the voltaic series or which have a more negative E cell value (greater reduction power)

The metal  : d. Fe(s) and Al(s)

7 0
2 years ago
If 16.9 kg of Al2O3(s), 57.4 kg of NaOH(l), and 57.4 kg of HF(g) react completely, how many kilograms of cryolite will be produc
hodyreva [135]

Answer: 69.72 kg of cryolite will be produced.

Explanation:

The balanced chemical equation is:

Al_2O_3(s)+6NaOH(l)+12HF(g)\rightarrow 2Na_3AlF_6+9H_2O

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

moles of Al_2O_3 = \frac{16.9\times 1000g}{102g/mol}=165.7moles

moles of NaOH = \frac{57.4\times 1000g}{40g/mol}=1435moles

moles of HF = \frac{57.4\times 1000g}{20g/mol}=2870moles

As 1 mole of Al_2O_3 reacts with 6 moles of NaOH

166 moles of  Al_2O_3 reacts with = \frac{6}{1}\times 166=996 moles of NaOH

As 1 mole of Al_2O_3 reacts with 12 moles of HF

166 moles of  Al_2O_3 reacts with = \frac{12}{1}\times 166=1992 moles of HF

Thus Al_2O_3 is the limiting reagent.

As 1 mole of Al_2O_3 produces = 2 moles of cryolite

166 moles of  Al_2O_3 reacts with = \frac{2}{1}\times 166=332 moles of cryolite

Mass of cryolite (Na_3AlF_6) = moles\times {\text {molar mass}}=332mol\times 210g/mol=69720g=69.72kg

Thus 69.72 kg of cryolite will be produced.

8 0
2 years ago
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