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hichkok12 [17]
3 years ago
7

WILL GIVE BRAINLESS IF ALL ANSWER ARE CORRECT

Chemistry
1 answer:
ella [17]3 years ago
8 0

Answer:

See explanation

Explanation:

1) C

2) True

3) A

4) C

5) A

6) Both. Some species that rely on the limiting factors will be harmed and other species that are prey to those species relying on limiting factors will be benefited.  

7) B

9) Decrease

10) D

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using the equation 2h2+o2-->2h2o, if 192g of oxygen are produced, how many grams of hydrogen must react with it
UkoKoshka [18]
The balanced chemical reaction is:

<span>2H2+O2-->2H2O
</span>
To determine the mass of hydrogen that is needed, we need use the initial amount of oxygen and relate it to hydrogen from the reaction given. We do as follows:

192 g O2 ( 1 mol O2 / 32 g O2) ( 2 mol H2 / 1 mol O2 ) ( 2.02 g H2 / 1 mol H2 ) = 24.24 g H2
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3 years ago
Use the given figure to complete the statement below.
MakcuM [25]

Easy, its vertical :3


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Which sequence repesent matter that is losing energy
astra-53 [7]

Which sequence repesent matter that is losing energy

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HOPE THIS HELPS :)

5 0
3 years ago
A piece of metal with a mass of 142 g is placed in a 50 mL graduated cylinder. The water level rises from 20 mL to 40 mL. What i
zheka24 [161]

Explanation:

The end goal of this question is to find density. Density can be found using the following formula:

D=m/v

D=Density

m=mass

v=volume

Therefore we need mass and volume to find density. Mass is already given in the question as 142g. All we have left is volume. When a solid is placed in water in a graduated cylinder the volume goes up. This means if you subtract the volume after the metal was placed from before it was placed, you can find the volume of the metal. Therefore the volume of the metal is 40mL-20mL=20mL. However typically, volume is found in liters so the volume should be .04L-.02L=0.02L. Now that we have volume and mass we can find density using the formula d=m/v. So 142/.02=7,100 grams per liget or 7.1 kilograms per liter. This answer seems unrealistic so I would double check with your teacher about the question.

Hope I helped, 2Trash4U

5 0
3 years ago
A standard lanthanum solution is prepared by dissolving 0.1968 grams of lanthanum oxide (La2O3) in excess nitric acid and diluti
sweet-ann [11.9K]

Answer:

1.208x10⁻³M and 392.5ppm La(NO3)3

Explanation:

The reaction that occurs is:

La2O3 + 6HNO3 → 2La(NO3)3 + 3H2O

Molarity is defined as the moles of solute (In this case, LaO3) per liter of solution. And ppm, are mg of solute per liter of solution.

To solve this question we must find the moles of La(NO3)3 produced and its mass in milligrams to find molarity and ppm:

<em>Moles La2O3 -Molar mass: 325.81g/mol-</em>

0.1968g * (1mol / 325.81g) = 6.04x10⁻⁴ moles La2O3

<em>Moles La(NO3)3:</em>

6.04x10⁻⁴ moles La2O3 * (2mol La(NO3)3 / 1mol La2O3) = 1.208x10⁻³ moles La(NO3)3

<em>Molarity:</em>

1.208x10⁻³ moles La(NO3)3 / 1L =

<h3>1.208x10⁻³M</h3>

<em>Mass La(NO3)3 -Molar mass: 324.92g/mol-</em>

1.208x10⁻³ moles La(NO3)3 * (324.92g / mol) = 0.392.5g La(NO3)3

In mg:

392.5mg La(NO3)3 / 1L =

392.5ppm La(NO3)3

7 0
3 years ago
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