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sergeinik [125]
3 years ago
15

I have no clue what this is asking me

Chemistry
1 answer:
Lana71 [14]3 years ago
4 0

The difference between the enthalpy of H2O(I) and H20(g) is H2O(I) will have less energy than compared to H2O(g).                                                

<u>Explanation</u>:

  • The enthalpy of H20(I) is more stable than H20(g) because H20(I) will have more liquid and H2O(g) will have more gas. The enthalpy of H20(I) is very exothermic than H2O(g). H20(I) has lesser energy than compared to gas because it has particles weaker than ice.
  • So it is necessary to specify the physical state of water in the thermochemical equation. ΔH=ΔHgas−ΔHliquid.                                                                                                                                        

         

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What is the pH of a 2.0 x 10^-4 M solution of nitric acid (HNO3)
Semmy [17]

Hello!

datos:

Molarity = 2.0*10^{-4}\:M\:(mol/L)


ps: The ionization constant of the nitric acid is strong (100% ionized in water) or completely dissociates in water, so the pH will be:

pH = - log\:[H_3O^+]

pH = - log\:[2*10^{-4}]

pH = 4 - log\:2

pH = 4 - 0.30

\boxed{\boxed{pH = 3.70}}\end{array}}\qquad\checkmark

Note:. The pH <7, then we have an acidic solution.

I Hope this helps, greetings ... DexteR!

3 0
4 years ago
Read 2 more answers
A gas has a volume of 50.0 cm3 at a temperature of -73°c. what volume would the gas occupy at a temperature of -123°c if the pre
vaieri [72.5K]

Boyle’s Law illustrates the inverse relationship of volume and pressure. It follows the formula  p1V1 = P2V2 , where P1V1 denotes initial pressure and volume  and P2V2 denotes values of pressure and  volume.

Now, let us work out for what is asked above.
a. if the pressure is doubled
50.0 p = V x 2p 
V = 50.0 p / 2p

= 50.0 /2

= 25.0 m^3 
b. if the pressure is cut in half
50.0 p = V x p/2 
100 p = V x p 
V = 100 m^3 
c. if the pressure is tripled
50.0 p = V x 3p 
V = 50.0 p / 3p

= 50.0 /3

=16.7 m^3 

<span> </span>

7 0
3 years ago
How many grams of ammonium chloride (gram formula mass= 53.5 g) are contained in .500 L of a 2.00 M solution?
Elza [17]

Answer:

53.5g of NH4Cl

Explanation:

First, we need to obtain the number of mole of NH4Cl. This is illustrated below:

Volume = 0.5L

Molarity = 2M

Mole =?

Molarity = mole /Volume

Mole = Molarity x Volume

Mole = 2 x 0.5

Mole = 1mole

Now, let us convert 1mole of NH4Cl to gram. This is illustrated below:

Molar Mass of NH4Cl = 53.5g/mol

Number of mole = 1

Mass =?

Number of mole = Mass /Molar Mass

Mass = number of mole x molar Mass

Mass = 1 x 53.5

Mass = 53.5g

Therefore, 53.5g of NH4Cl is contained in the solution.

8 0
3 years ago
Determine the rate of a reaction that follows the rate law rate = k a m b i where
ikadub [295]
(missing part of your question):
when we have K = 1 x 10^-2 and [A] = 2 M & [B] = 3M & m= 2 & i = 1
So when the rate = K[A]^m [B]^i
and when we have m + i = 3 so the order of this reaction is 3 So the unit of K is L^2.mol^-2S^-1
So by substitution:
∴ the rate = (1x 10 ^-2 L^-2.mol^-2S^-1)*(2 mol.L^-1)^2*(3mol.L^-1)
                 = 0.12 mol.L^-1.S^-1
6 0
4 years ago
Name the two products when calcium carbonate (CaCO3) is heated
trapecia [35]

Answer:

The products are Calcium oxide and Carbon dioxide.

Explanation:

When calcium carbonate is heated, thermal decomposition occurs.

Calcium calcium → Calcium oxide + Carbon dioxide

3 0
3 years ago
Read 2 more answers
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