The circuit is working, and all three bulbs are lit. If a switch at C is opened, what will happen to the circuit?
2 answers:
The correct answer is option <span>D. All three bulbs will go out.
</span>
In the circuit, all the bulbs are connected in series with each other. When the <span>switch at C is opened, the circuit is broken (consider the wire is broken). It is shown in diagram as well (attached).
Hence, when the circuit is broken, the current will not reach the bulbs 2 & 3. And, the connection will be disrupted, So all the bulbs will blow out.
Hence, D is the correct option. </span>
</span>
In the circuit, all the bulbs are connected in series with each other. When the <span>switch at C is opened, the circuit is broken (consider the wire is broken). It is shown in diagram as well (attached).
Hence, when the circuit is broken, the current will not reach the bulbs 2 & 3. And, the connection will be disrupted, So all the bulbs will blow out.
Hence, D is the correct option. </span>
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Answer:
B = 0.157 T
Explanation:
Given that,
Length of the solenoid, l = 8 cm = 0.08 m
Number of turns in the wire, N = 2000
Current, I = 5 A
We need to find the strength of the magnetic field at the center of the solenoid. It is given by the formula as follows :
, N is number of turns per unit length of solenoid.
So,
So, the magnetic field at the center of the solenoid is 0.157 T.