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photoshop1234 [79]
2 years ago
13

A 2.0   kg 2.0kg2, point, 0, start text, k, g, end text cart moving right at 5.0   m s 5.0 s m ​ 5, point, 0, start fraction, st

art text, m, end text, divided by, start text, s, end text, end fraction on a frictionless track collides with a 3.0   kg 3.0kg3, point, 0, start text, k, g, end text cart initially at rest. The 2.0   kg 2.0kg2, point, 0, start text, k, g, end text cart has a final speed of 1.0   m s 1.0 s m ​ 1, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction to the left. What is the final speed of the 3.0   kg 3.0kg3, point, 0, start text, k, g, end text cart?
Physics
2 answers:
butalik [34]2 years ago
7 0
Yes así le tienes que hacer para aprender
Elena L [17]2 years ago
3 0

Answer:  The answer is 4.0 m/s.

Explanation: khan acadmey.

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A soccer player heads the ball and sends it flying vertically upwards at a speed of 18.0 m/s . How high above the players ' head
Darya [45]

Answer:

<em>The ball travels up to 16.53 meters above the player's head</em>

Explanation:

<u>Vertical Launch Upwards</u>

In a vertical launch upwards, an object is launched vertically up from a height H without taking into consideration any kind of friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

\displaystyle h_m=H+\frac{v_o^2}{2g}

The initial speed of the soccer ball is vo=18 m/s. The initial height can be assumed to be zero because we are required to find the maximum height with respect to the player's head, where the vertical motion was initiated.

Calculate the maximum height:

\displaystyle h_m=\frac{18^2}{2\cdot 9.8}

h_m=16.53\ m

The ball travels up to 16.53 meters above the player's head

5 0
3 years ago
A race car has a velocity of 382 km/h to the right. If the car’s mass is 705 kg and the driver’s mass is 65 kg, what force is ne
Lady bird [3.3K]

Answer:

Given: Vi = 382 km/h, Vf = 0 km/h, Mc = 705 kg, Md = 65 kg, Δt = 12

Required: Δx

F = Δp / Δt

  = \frac{(Mc+Md)Vf-(Mc+Md)Vi}{t} \\\\= 6.81 * 10x^{3} N [left]\\\\x=\frac{1}{2} (Vi+Vf)\\ \\ = 637m[right]

6 0
2 years ago
A ball of mass 6.00 kg moving with a
cestrela7 [59]

Answer: v=8,7m/s

Explanation:

Quando dois corpos andam aglutinados, significam que têm a mesma velocidade, e a quantidade de movimento antes de uma colisão, é igual á quantidade de tempo depois dessa colisão

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2 years ago
An object experiences a 8.9 N force and accelerates 6 m/sec2. What is the object's
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b stupidrwfs

planation:

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3 years ago
you record the length of different people's feet is this an example of a controlled experiment true or false
never [62]
False you cant control the size of feet
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