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Vsevolod [243]
3 years ago
9

A 8.0-cm long solenoid has 2000 turns of wire and carries a current of 5.0-A. Calculate the strength of the magnetic field at th

e center of the solenoid in teslas.
Physics
1 answer:
CaHeK987 [17]3 years ago
6 0

Answer:

B = 0.157 T

Explanation:

Given that,

Length of the solenoid, l = 8 cm = 0.08 m

Number of turns in the wire, N = 2000

Current, I = 5 A

We need to find the strength of the magnetic field at the center of the solenoid. It is given by the formula as follows :

N=\mu_o nI, N is number of turns per unit length of solenoid.

So,

B=4\pi \times 10^{-7}\times \dfrac{2000}{0.08}\times 5\\\\=0.157\ T

So, the magnetic field at the center of the solenoid is 0.157 T.

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Explanation:

S.H.M is Simple Harmonic Motion

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For heat transfer purposes, an egg can be considered to be a 5.5-cm-diameter sphere having the properties of water. An egg that
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Answer:

The time taken is   t = 40007 sec  

Explanation:

From the question we are told that

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     The temperature of the boiling water T_b = 100^oC

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    The  final temperature is T_e_f = 74^oC

     The  thermal  conductivity of water is k = 0.607 W/m^oC

     The diffusivity of the egg \alpha = 0.146 * 10^{-6} m^2 /s

Using one term approximation

We have the

            \frac{T_e_f - T_b}{T_e - T_b}  = Ae^{-\lambda ^2 \tau}

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          0.2717= 1.9942 e^{-9.383 \tau}

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           -1.993 =  -9.383\  \tau

          \tau =  0.2124

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substituting value  is  

         = \frac{0.2124 * 2.75 *10^{-2}}{0.146 *10^{-6}}

         t = 40007 sec  

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