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Vsevolod [243]
3 years ago
9

A 8.0-cm long solenoid has 2000 turns of wire and carries a current of 5.0-A. Calculate the strength of the magnetic field at th

e center of the solenoid in teslas.
Physics
1 answer:
CaHeK987 [17]3 years ago
6 0

Answer:

B = 0.157 T

Explanation:

Given that,

Length of the solenoid, l = 8 cm = 0.08 m

Number of turns in the wire, N = 2000

Current, I = 5 A

We need to find the strength of the magnetic field at the center of the solenoid. It is given by the formula as follows :

N=\mu_o nI, N is number of turns per unit length of solenoid.

So,

B=4\pi \times 10^{-7}\times \dfrac{2000}{0.08}\times 5\\\\=0.157\ T

So, the magnetic field at the center of the solenoid is 0.157 T.

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Answer:

Stretch in the spring = 0.1643 (Approx)

Explanation:

Given:

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Computation:

Tension force in the spring  (T) = ma

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Stretch in the spring = 18.9 / 115

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A) a neutron pushing on another neutron.

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