Answer:
Step-by-step explanation:
<u>Given expression is:</u>
= 10 + 3(12 ÷ (3x))
Put x = 2 nd use PEDMAS [Parenthesis Exponents Division Multiplication Addition Subtraction "in that order"]
= 10 + 3(12 ÷ (3)(2))
Solve Parenthesis
= 10 + 3(12 ÷ 6)
Now, Divide
= 10 + 3(2)
Now, Multiply
= 10 + 6
Now, Add
= 16
Hope this helped!
<h3>~AH1807</h3>Answer:
This approach to (0,0) also gives the value 0
Step-by-step explanation:
Probably, you are trying to decide whether this limit exists or not. If you approach through the parabola y=x², you get
It does not matter if x>0 or x<0, the |x| on the denominator will cancel out with an x on the numerator, and you will get the term x²/(√(1+x²) which tends to 0.
If you want to prove that the limit doesn't exist, you have to approach through another curve and get a value different from zero.
However, in this case, the limit exists and its equal to zero. One way of doing this is to change to polar coordinates and doing a calculation similar to this one. Polar coordinates x=rcosФ, y=rsinФ work because the limit will only depend on r, no matter the approach curve.