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Leona [35]
3 years ago
5

Write an equation of the line passing through the point A(2, 0) that is parallel to the line y = 3x−5 .

Mathematics
1 answer:
sammy [17]3 years ago
4 0
Hello,

In order for lines to be parallel to each other, they need to have the same slope. So, let's plug in the points and slope for point-slope form.

The equation for point-slope form is: y-y1 = m (x-x1)

Let's plug in the points into the equation. 
y-5 = m (x-0), and then let's plug in the slope for "m" : y-5 = 3 (x-0).

After plugging the numbers in, the equation is simplified to y-5 = 3 (x-0). Then distribute the 3 to the parenthesis. y-5 = 3x. To get y by itself, you need to add 5 to both sides. After that, the equation parallel to that equation is: y = 3x + 5.

Hope this helps! =)
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8 0
3 years ago
Read 2 more answers
Solve 2x2 − 12x + 20 = 0.<br><br> 3 ± i<br> 3 ± 2i<br> 1 ± 2i<br> 2 ± 3i
makkiz [27]
This is the concept of quadratic equations, solving the equation 2x^2-12x+20=0 using the formula we get:
x=[-b+/-sqrt(b^2-4ac)]/(2a)
from our equation, a=2,b=-12 and c=20
x=[-(-12+/-sqrt((-12)^2-4*2*20)]/(2*2)
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