Consider all parabolas:
1.

When x=-3, y=-1, then the point (-3,-1) is vertex of this first parabola.
2.

When x=-4, y=-4, then the point (-4,-4) is vertex of this second parabola.
3.

When x=2.5, y=20.25, then the point (2.5,20.25) is vertex of this third parabola.
4.

When x=3.5, y=19.25, then the point (3.5,19.25) is vertex of this fourth parabola.
5.

When x=-1.75, y=-1.125, then the point (-1.75,-1.125) is vertex of this fifth parabola.
6.

When x=2, y=13, then the point (2,13) is vertex of this sixth parabola.
Answer:
Given : BRDG is a kite that is inscribed in a circle,
With BR = RD and BG = DG
To prove : RG is a diameter
Proof:
Since, RG is the major diagonal of the kite BRDG,
By the property of kite,
∠ RBG = ∠ RDG
Also, BRDG is a cyclic quadrilateral,
Therefore, By the property of cyclic quadrilateral,
∠ RBG + ∠ RDG = 180°
⇒ ∠ RBG + ∠ RBG = 180°
⇒ 2∠ RBG = 180°
⇒ ∠ RBG = 90°
⇒ ∠ RDG = 90°
Since, Angle subtended by a diameter or semicircle on any point of circle is right angle.
⇒ RG is the diameter of the circle.
Hence, proved.
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