Answer:
Solid Osmium transition metal reacts with Oxygen gas to produce solid Osmium tetroxide.
Os(s) + 2O₂(g) -> OsO₄(s)
Explanation:
Osmium tetroxide is another way of writing Osmium (VIII) oxide.
Leaving powdered osmium exposed to air in a room will slowly create osmium tetroxide at room temperature.
Similarly, osmium tetroxide vapor will readily be released from a liquid solution at room temperature.
Answer:
For every pound lost, replace it with 16 to 20 ounces of fluid
Answer:
120g
Explanation:
Step 1:
We'll begin by writing the balanced equation for the reaction.
Sn + 2HF —> SnF2 + H2
Step 2:
Determination of the number of mole HF needed to react with 3 moles of Sn.
From the balanced equation above,
1 mole of Sn and reacted with 2 moles of HF.
Therefore, 3 moles Sn will react with = 3 x 2 = 6 moles of HF.
Step 3:
Conversion of 6 moles of HF to grams.
Number of mole HF = 6 moles
Molar Mass of HF = 1 + 19 = 20g/mol
Mass of HF =..?
Mass = number of mole x molar Mass
Mass of HF = 6 x 20
Mass of HF = 120g
Therefore, 120g of HF is needed to react with 3 moles of Sn.
The answer is D. I did that and i got it right.
Answer:
Molality = 1.13 m
Explanation:
Molality is defined as the moles of the solute present in 1 kilogram of the solvent.
Given that:
Mass of 
= 26.5 g
Molar mass of = 32.04 g/mol
The formula for the calculation of moles is shown below:
Thus,
Mass of water = 735 g = 0.735 kg ( 1 g = 0.001 kg )
So, molality is:
<u>Molality = 1.13 m</u>
