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nata0808 [166]
4 years ago
14

Please help me as soon as possible.

Mathematics
1 answer:
love history [14]4 years ago
7 0
Total = Principal * (1 + rate/n)^(n*years)
where "n" is the number of compounding periods per year
Total = 6,000 * (1 + .06/4)^(4*5)
Total = 6,000 * (1 + .015)^(20)
Total = 6,000 * <span> <span> <span> 1.3468550066 </span> </span> </span>
Total = <span> <span> <span> 8,081.13</span></span></span>

Source:
http://www.1728.org/compint.htm


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Answer:

C

This is the answer

(x + 3)(5x + 2) \\ x =  - 3 \:  \: or \:  \: x =   - \frac{2}{5}

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Which of the following functions is graphed below?
sasho [114]

Answer:

2nd choice B.

Step-by-step explanation:

You can use the options A-D to help you eliminate pretty quickly without actually graphing

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Second choice Possible

Third choice... I'm just going to look at one of the parts... x^2+4 for x<=1 says we should have part of a parabola to the left of x=1 (inclusive) but there is not parabola in our visual

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Simplify the expressions by combining like terms<br><br> 10r - 5r + 3r - 8r
Yuri [45]

Answer:

0

Step-by-step explanation:

Combine like terms, perform the operations with the coefficients of the variable, then write the variable.

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7 0
3 years ago
Read 2 more answers
Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that
RUDIKE [14]

The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Given a function f(x)=9/x,a=-4.

We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.

The taylor series of a function f(x)=f(a)+f^{1}(a)(x-a)/1!+ f^{11}(a)(x-a)^{2} /2! +f^{111}(a)(x-a)a^{3}/3!+..........

Where the terms in f prime f^{1}(a) represent the derivatives of x valued at a.

For the given function.f(x)=8/x and a=-4.

So,f(a)=f(-4)=8/(-4)=-2.

f^{1}(a)=f^{1}(-4)=-8/(-4)^{2}

=-8/16

=-1/2

The series of f(x) is as under:

f(x)=f(-4)+f^{1}(-4)(x+4)/1!+  f^{11}(-4)(x+4)^{2}/2!.............

=8/(-4)-8/(-4)^{2} (-4)(x+4)/1!+  24/(-4)^{3} (-4)(x+4)^{2}/2!.............

=-2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Learn more about taylor series at brainly.com/question/23334489

#SPJ4

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1 year ago
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