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erik [133]
4 years ago
8

How much heat is required to raise the temperature of 6.2 x 102 g of aluminum by 20°C (specific heat of aluminum =0.21 cal/g°C?

Please show all work for credit.
Chemistry
1 answer:
RoseWind [281]4 years ago
8 0
The heat required to raise the temperature of a certain mass of sample to a specific temperature change, we use the formula mCpΔT where m is mass, Cp is the specific heat of the substance and ΔT is the temperature change. In this case, we substitute and form 6.2 x102 g x 0.21 cal/g C *20 C equal to 2604 calories.
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A pool is 60.0 m long and 35.0 m wide. How many mL of water are needed to fill the pool to an average depth of 6.35 ft? Enter yo
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Answer:

4.07 × 10⁹ mL

Explanation:

Step 1: Given data

Length of the pool (L): 60.0 m

Width of the pool (W): 35.0 m

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Step 2: Convert "D" to m

We will use the relationship 1 m = 3.28 ft

6.35ft \times \frac{1m}{3.28ft} = 1.94m

Step 3: Calculate the volume of water (V)

We will use the following expression.

V = L \times W \times D = 60.0m \times 35.0m \times 1.94 m = 4.07 \times 10^{3} m^{3}

Step 4: Convert "V" to mL

We will use the relationship 1 m³ = 10⁶ mL.

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