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MrRissso [65]
2 years ago
14

400 ms^2/0.080 s solve

Chemistry
1 answer:
Nana76 [90]2 years ago
5 0

Answer: 5000ms^2 s

Explanation:

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PLEASE HELP
nata0808 [166]

Answer:

Is this math? Cause as a fourth grader, I can do Algebra, but not this.

Explanation:

7 0
1 year ago
Four liquids are described in the table below. Use the second column of the table to explain the order of their freezing points,
KIM [24]
Transcribed image text: Four liquids are described in the table below. Use the second column of the table to explain the order of their freezing points, and the third column to explain the order of their boiling points. For example, select '1' in the second column next to the liquid with the lowest freezing point. Select '2' in the second column next to the liquid with the next higher freezing point, and so on. In the third column, select '1' next to the liquid with the lowest boiling point, '2' next to the liquid with the next higher boiling point, and so on. Note: the density of water is 1.00g/mL .
7 0
2 years ago
Why doesnt ammonia support combustion?
earnstyle [38]
We need the reading for this I think
4 0
2 years ago
Determine the volume occupied by 0.352 mole of a gas at 25⁰C if the pressure is 81.8 kPa.
lions [1.4K]
Data:
p (pressure) = 81.8 kPa = 81.8*10³ Pa ≈ 8.07 atm
v (volume) = ? (in L)
n (number of mols) = 0.352 mol
R (Gas constant) = 0.082 (atm*L/mol*K)
T (temperature) = 25ºC converting to Kelvin, we have:
TK = TC + 273 → TK = 25 + 273 → TK = 298

Formula:
p*V =n*R*T

Solving:
p*V =n*R*T
8.07*V = 0.352*0.082*298
8.07V \approx 8.60
V \approx  \frac{8.60}{8.07}
\boxed{\boxed{V \approx 1.06\:L}}
7 0
3 years ago
How many moles of carbon dioxide are produced when 5.12 mol of propane gas is burned in excess oxygen? C3H8(g) + 5O2(g) → 3CO2(g
maxonik [38]

Answer:

15.4 mol CO₂

Explanation:

5.12 mol C₃H₈ × (3 mol CO₂ / mol C₃H₈) ≈ 15.4 mol CO₂

4 0
2 years ago
Read 2 more answers
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